我尝试使用此代码来获取我的照片:
IGraphBuilder _graph = null;
ISampleGrabber _grabber = null;
IBaseFilter _sourceObject = null;
IBaseFilter _grabberObject = null;
IMediaControl _control = null;
// Create the main graph
_graph = Activator.CreateInstance(Type.GetTypeFromCLSID(FilterGraph)) as IGraphBuilder;
// Create the webcam source
_sourceObject = FilterInfo.CreateFilter(_monikerString);
// Create the grabber
_grabber = Activator.CreateInstance(Type.GetTypeFromCLSID(SampleGrabber)) as ISampleGrabber;
_grabberObject = _grabber as IBaseFilter;
// Add the source and grabber to the main graph
_graph.AddFilter(_sourceObject, "source");
_graph.AddFilter(_grabberObject, "grabber");
IPin pin = _sourceObject.GetPin(PinDirection.Output, 0);
IAMStreamConfig streamConfig = pin as IAMStreamConfig;
int count = 0, size = 0;
streamConfig.GetNumberOfCapabilities(out count, out size);
int width = 0, height = 0;
AMMediaType mediaType = null;
AMMediaType mediaTypeCandidate = null;
for(int index = 0; index < count; index++) {
VideoStreamConfigCaps scc = new VideoStreamConfigCaps();
int test = streamConfig.GetStreamCaps(index, out mediaTypeCandidate, scc);
if(mediaTypeCandidate.MajorType == MediaTypes.Video && mediaTypeCandidate.SubType == MediaSubTypes.YUY2) {
VideoInfoHeader header = (VideoInfoHeader)Marshal.PtrToStructure(mediaTypeCandidate.FormatPtr, typeof(VideoInfoHeader));
if(header.BmiHeader.Width == 1280 && header.BmiHeader.Height == 720) {
width = header.BmiHeader.Width;
height = header.BmiHeader.Height;
if(mediaType != null)
mediaType.Dispose();
mediaType = mediaTypeCandidate;
} else
mediaTypeCandidate.Dispose();
} else
mediaTypeCandidate.Dispose();
}
streamConfig.SetFormat(mediaType);
它有效,但我没有看到由此代码生成的图像:
uint pcount = (uint)(_capGrabber.Width * _capGrabber.Height * PixelFormats.Bgr32.BitsPerPixel / 8);
// Create a file mapping
_section = CreateFileMapping(new IntPtr(-1), IntPtr.Zero, 0x04, 0, pcount, null);
_map = MapViewOfFile(_section, 0xF001F, 0, 0, pcount);
// Get the bitmap
BitmapSource = Imaging.CreateBitmapSourceFromMemorySection(_section, _capGrabber.Width,
_capGrabber.Height, PixelFormats.Bgr32, _capGrabber.Width * PixelFormats.Bgr32.BitsPerPixel / 8, 0) as InteropBitmap;
_capGrabber.Map = _map;
// Invoke event
if (NewBitmapReady != null)
{
NewBitmapReady(this, null);
}
因为SubMediaTyp是YUY2。如何在此代码中添加转换器?我已经阅读了一些关于ColorConvert的内容,可以将其添加到IGraphBuilder中。这有什么作用?
答案 0 :(得分:0)
我不希望CreateBitmapSourceFromMemorySection
接受除flavors of RGB以外的任何其他内容。它更不可能接受YUY2
媒体类型,因此您需要DirectShow管道将视频流转换为RGB,然后再将其导出为托管位图/成像对象。
为实现此目的,您通常会将Sample Grabber过滤器初始化为24位RGB子类型,并让DirectShow自动提供必要的转换器。
请在此处查看详细说明和代码段:DirectShow: Examples for Using SampleGrabber for Grabbing a Frame and...
media.majorType = MediaType.Video;
media.subType = MediaSubType.RGB24;
media.formatPtr = IntPtr.Zero;
hr = sampGrabber.SetMediaType(media);