RANK（）Over Partition BY不工作

Question

当我运行下面的代码时，ROWID始终为1。 对于具有相同信用值的每个项目，我需要ID从1开始。

;WITH CTETotal AS (SELECT
     TranRegion
    ,TranCustomer
    ,TranDocNo
    ,SUM(TranSale) 'CreditValue'
FROM dbo.Transactions

LEFT JOIN customers AS C 
      ON custregion = tranregion 
      AND custnumber = trancustomer
LEFT JOIN products AS P
      ON prodcode = tranprodcode

GROUP BY
TranRegion
,TranCustomer
,TranDocNo)

SELECT
       r.RegionDesc
      ,suppcodedesc
      ,t.tranreason as [Reason]
      ,t.trandocno as [Document Number]
      ,sum(tranqty) as Qty
      ,sum(tranmass) as Mass
      ,sum(transale) as Sale
      ,cte.CreditValue AS 'Credit Value'
      ,RANK() OVER (PARTITION BY cte.CreditValue ORDER BY cte.CreditValue)AS ROWID

FROM transactions t

LEFT JOIN dbo.Regions AS r    
      ON r.RegionCode = TranRegion  

LEFT JOIN CTETotal AS cte
      ON cte.TranRegion = t.TranRegion
      AND cte.TranCustomer = t.TranCustomer
      AND cte.TranDocNo = t.TranDocNo

GROUP BY 
       r.RegionDesc
      ,suppcodedesc
      ,t.tranreason
      ,t.trandocno
      ,cte.CreditValue

ORDER BY CreditValue ASC

修改

400的所有信用值必须将ROWID设置为1.并且所有200的信用值必须将ROWID设置为2.依此类推。

Answer 1

你需要这样的东西吗？

with cte (item,CreditValue)
as
(
select 'a',8 as CreditValue union all
select 'b',18 union all
select 'a',8 union all
select 'b',18 union all
select 'a',8 
) 
select CreditValue,dense_rank() OVER (ORDER BY item)AS ROWID from cte

结果

CreditValue ROWID
----------- --------------------
8           1
8           1
8           1
18          2
18          2

在您的代码中替换

,RANK() OVER (PARTITION BY cte.CreditValue ORDER BY cte.CreditValue)AS ROWID 

通过

,DENSE_RANK() OVER (ORDER BY cte.CreditValue)AS ROWID 

Answer 2

您不必使用PARTITION，只需使用DENSE_RANK() OVER (ORDER BY cte.CreditValue)

Answer 3

我认为问题出在RANK（）OVER（PARTITION BY子句

）上

您必须按项目而不是CreditValue

对其进行分区

Answer 4

试试这个

RANK（）OVER（由cte.CreditValue ORDER by cte.RegionDesc分割）AS ROWID

Answer 5

编辑：这里的问题实际上不是子查询的嵌套，它可能基于 partition by 具有真正使每一行唯一（或 1）的列

而不是像这样在复杂的查询中排名

select 
   rank() over(partition by...),
   *
from
   data_source
join table1
join table2
join table3
join table4
order by
   some_column

在结果数据集上尝试 rank() 或 row_number()，而不是在其中。

例如，使用上面的查询，删除 rank() 并以这种方式实现：

select
   rank() over(partition by...),
   results.*
from (
    select 
       *
    from
       data_source
    join table1
    join table2
    join table3
    join table4
    order by
       some_column
) as results