Question

可能重复：
Calculate a Running Total in SqlServer

我需要在ms-sql server中获取一列的累积（运行）总数。即如果有一个名为“Marks”的列，那么对应于每行的累积和将是当前行和前一行的总和。我们可以在不使用连接的情况下获得结果吗？因为我的查询非常大。

我已经包含了一个示例表和数据：

CREATE TABLE "SCORE_CHART" 
   (    
        "STUDENT_NAME" NVARCHAR(20), 
        "MARKS" INT
   )

INSERT INTO SCORE_CHART (STUDENT_NAME, MARKS) VALUES ('STUD1', 95);
INSERT INTO SCORE_CHART (STUDENT_NAME, MARKS) VALUES ('STUD2', 90);
INSERT INTO SCORE_CHART (STUDENT_NAME, MARKS) VALUES ('STUD3', 98);

SELECT STUDENT_NAME, MARKS FROM SCORE_CHART;

预期结果： enter image description here

在oracle中，写起来很容易：

SELECT 
  STUDENT_NAME,
  MARKS,
  SUM(MARKS) OVER (ORDER BY STUDENT_NAME) CUM_SUM
FROM SCORE_CHART
ORDER BY STUDENT_NAME;

提前致谢。

Answer 1

从2012年开始支持相同的查询。在旧版本中，有几种方法。请参阅此http://www.sqlperformance.com/2012/07/t-sql-queries/running-totals

Answer 2

试试这个：

您只需加入相同的表格就可以获得累积金额

SELECT S1.STUDENT_NAME, S1.MARKS ,sum(S2.MARKS) CUM_SUM
FROM SCORE_CHART S1 join SCORE_CHART S2
on S1.STUDENT_NAME>=S2.STUDENT_NAME
group by S1.STUDENT_NAME, S1.MARKS 
order by S1.STUDENT_NAME, S1.MARKS

SQL Fiddle demo

Answer 3

你说没有加入，申请怎么样？ ;）

SELECT STUDENT_NAME, MARKS, running.total
FROM SCORE_CHART a
cross apply 
(
    select SUM(marks) total 
    from score_chart b
    where b.student_name <= a.student_name
) running
ORDER BY STUDENT_NAME;

使用student_name的索引速度应该没问题！

Answer 4

检查递归CTE的查询。

;with CTE as (select ROW_NUMBER() over (order by (select 0)) as id,STUDENT_NAME,MARKS from SCORE_CHART)
,CTE1 as (

select id,STUDENT_NAME,marks,marks as CUM_SUM from CTE where id=1
UNION ALL
select c.id,c.STUDENT_NAME,c.marks,c.marks+c1.CUM_SUM as CUM_SUM from CTE1 c1 inner join CTE c on c.id-1=c1.id)
select * from CTE1

Answer 5

使用递归CTE来实现这一目标。

Answer 6

JUSt做一个连接似乎不保证顺序，但最终答案确定：

select 
  x.STUDENT_NAME
  , sum(y.marks) marks
from 
    SCORE_CHART x
       join SCORE_CHART y
          on x.STUDENT_NAME <= y.STUDENT_NAME
group by x.STUDENT_NAME
order by x.STUDENT_NAME

似乎是NO JOINS规则 - 将重新思考

编辑 - 现在运行正常：LIVE FIDDLE HERE

创建数据

CREATE TABLE "SCORE_CHART"     
(             
  "STUDENT_NAME" NVARCHAR(20),          
  "MARKS" INT    
)  
INSERT INTO SCORE_CHART (STUDENT_NAME, MARKS) 
VALUES 
('STUD1', 95),
('STUD2', 90),
('STUD3', 98)

使用递归CTE：

 ;WITH 
    init_cte(row,STUDENT_NAME,MARKS) 
    AS
        (
        SELECT 
        ROW_NUMBER() OVER (ORDER BY STUDENT_NAME),
        STUDENT_NAME,
        MARKS
        FROM SCORE_CHART
        )
    ,MinMax_cte(MinRow,MaxRow)  AS (SELECT MIN(row),MAX(row) FROM init_cte)

    ,recursive_cte (row,STUDENT_NAME,MARKS,RUNNING_MARKS) AS 
      (
         SELECT row,STUDENT_NAME,MARKS,MARKS 
            FROM init_cte 
            WHERE row = (SELECT MinRow FROM  MinMax_cte) 
         UNION ALL
         SELECT Y.row,y.STUDENT_NAME,y.MARKS,x.RUNNING_MARKS + y.MARKS
            FROM recursive_cte x
            INNER JOIN init_cte y
                ON y.row = x.row + 1
            WHERE y.row <= (SELECT [MaxRow] from MinMax_cte)
      )
SELECT * FROM recursive_cte

正如对你的评论中提到的那样OP有一个类似的问题HERE ON SO 在那个问题上，Sam Saffron提出了一种使用UPDATE进行总计运行的非常优雅的方法。这适用于您的数据：

使用上面创建的相同数据，但使用UPDATE技巧：

CREATE TABLE #t ( ROW int, STUDENT_NAME NVARCHAR(20) , MARKS int, MARKS_RUNNING int) 
INSERT INTO #t
SELECT
        ROW_NUMBER() OVER (ORDER BY STUDENT_NAME),
        STUDENT_NAME, 
        MARKS,
        0
FROM SCORE_CHART

DECLARE @total int  
SET @total = 0 
UPDATE #t SET marksrunning = @total, @total = @total + MARKS   

SELECT * FROM #t

MS Sql server中的累计总数

6 个答案: