Question

我想知道是否有人知道用于将制表符分隔文件读入数据表的高效c＃函数？

由于

Answer 1

当前使用LINQ方法.First()和.Skip()如果你需要在.Net 2.0上使用它，这两种方法都很容易重新创建

//even cooler as an extension method
static IEnumerable<string> ReadAsLines(string filename)
{
    using (var reader = new StreamReader(filename))
        while (!reader.EndOfStream)
            yield return reader.ReadLine();
}

static void Main()
{
    var filename = "tabfile.txt";
    var reader = ReadAsLines(filename);

    var data = new DataTable();

    //this assume the first record is filled with the column names
    var headers = reader.First().Split('\t');
    foreach (var header in headers)
        data.Columns.Add(header);

    var records = reader.Skip(1);
    foreach (var record in records)
        data.Rows.Add(record.Split('\t'));
}

Answer 2

public System.Data.DataTable GetDataTable(string strFileName)
{
    System.Data.OleDb.OleDbConnection conn = new System.Data.OleDb.OleDbConnection("Provider=Microsoft.Jet.OleDb.4.0; Data Source = " + System.IO.Path.GetDirectoryName(strFileName) + ";Extended Properties = \"Text;HDR=YES;FMT=TabDelimited\"");
    conn.Open();
    string strQuery = "SELECT * FROM [" + System.IO.Path.GetFileName(strFileName) + "]";
    System.Data.OleDb.OleDbDataAdapter adapter = new System.Data.OleDb.OleDbDataAdapter(strQuery, conn);
    System.Data.DataSet ds = new System.Data.DataSet("CSV File");
    adapter.Fill(ds);
    conn.Close();
    return ds.Tables[0];
 }

Answer 3

这是一种方法......

        var dt = new DataTable();
        dt.Columns.Add(new DataColumn("Column1", typeof(string)));
        dt.Columns.Add(new DataColumn("Column2", typeof(string)));
        dt.Columns.Add(new DataColumn("Column3", typeof(string)));

        var lines = File.ReadAllLines(@"c:\tabfile.txt");
        foreach( string line in lines )
            dt.Rows.Add(line.Split('\t'));

用于将分隔文件读入DataTable的高效功能

3 个答案: