.ajax呼叫没有到达我的控制器...不知道为什么

时间:2012-07-25 21:29:04

标签: asp.net-mvc jquery

我正在尝试向我的控制器发送一个Ajax调用并传回一个字符串......出于某种原因,我无法进入我的控制器...... 不确定我错过了什么......

$.ajax({
                url: dummyURL,
                success: function (result) {
                    $('#resultDiv').append('<b>' + result + '</b>');
                    setTimeout(function () {
                        window.location = RedirectUrl;
                    }, 1000);
                }
            });

这是我设置我的网址字符串的方式:

var dummyURL = '@Url.Action("AddPatient", "AddFoundPatient", new { FirstName = "-1", LastName = "-2", DOB = "-3", MRN = "-4", EMPIID = "-5", popID = (int)TempData["POPULATIONID"] })';

var FName = rowData['First_Name'];
            var LName = rowData['Last_Name'];
            var DOB = rowData['DOB'];
            var MRN = rowData['medipacId'];
            var EMPIID = rowData['EMPIID'];
            //Add Patient call
            var path = dummyURL.replace("-1", FName);
            path = path.replace("-2", LName);
            path = path.replace("-3", DOB);
            path = path.replace("-4", MRN);
            path = path.replace("-5", EMPIID);

这是我试图调用的Action方法......

public string AddFoundPatient(string FirstName, string LastName, string DOB, string MRN, string EMPIID, int popID)

这是我生成的查询字符串......

/AddFoundPatient/AddPatient?FirstName=BETTY &amp;LastName=WHITE &amp;DOB=1925-10-25 &amp;MRN=840108105 &amp;EMPIID=11011833 &amp;popID=2

我从未在我的行动中发表过侮辱性言论......我做错了什么?

1 个答案:

答案 0 :(得分:3)

控制器和操作混合

var dummyURL = '@Url.Action("AddFoundPatient", "AddPatient", new { FirstName = "-1", LastName = "-2", DOB = "-3", MRN = "-4", EMPIID = "-5", popID = (int)TempData["POPULATIONID"] })';