所以我会弹出这个AlertDialog
并在用户首次打开应用时说出正确的话。
然后他们可以选择点击CheckBox
,并在下次启动应用时停用该对话框。
启用CheckBox
无效。当应用程序完全关闭然后重新启动时,它会再次弹出警告对话框。有没有人看到我做的事情有什么问题?
public static final String PREFS_NAME = "MyPrefsFile1";
public CheckBox dontShowAgain;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
AlertDialog.Builder adb = new AlertDialog.Builder(this);
LayoutInflater adbInflater = LayoutInflater.from(this);
View eulaLayout = adbInflater.inflate(R.layout.custom_dialog, null);
dontShowAgain = (CheckBox)eulaLayout.findViewById(R.id.checkBox1);
adb.setView(eulaLayout);
adb.setTitle("Alert Dialog");
adb.setMessage("My Customer Alert Dialog Message Body");
adb.setPositiveButton("Ok", new DialogInterface.OnClickListener()
{
//CheckBox Confirm for Alert Dialog
public void onClick(DialogInterface dialog, int which) {
String checkBoxResult = "NOT checked";
if (dontShowAgain.isChecked()) checkBoxResult = "checked";
SharedPreferences settings = getSharedPreferences(PREFS_NAME, 0);
SharedPreferences.Editor editor = settings.edit();
editor.putString("skipMessage", checkBoxResult);
// Commit the edits!
editor.commit();
return;
}
});
adb.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
// Action for 'Cancel' Button
String checkBoxResult = "NOT checked";
if (dontShowAgain.isChecked()) checkBoxResult = "checked";
SharedPreferences settings = getSharedPreferences(PREFS_NAME, 0);
SharedPreferences.Editor editor = settings.edit();
editor.putString("skipMessage", checkBoxResult);
// Commit the edits!
editor.commit();
return;
}
});
//Preferences For Alert Dialog
SharedPreferences settings = getSharedPreferences(PREFS_NAME, 0);
String skipMessage = settings.getString("skipMessage", "NOT checked");
if (skipMessage !=("checked") )
adb.setIcon(R.drawable.icon);
adb.show();
}
以下是我的AlertDialog
XML
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/layout_root"
android:orientation="horizontal"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:padding="10dp"
>
<ImageView android:id="@+id/image"
android:layout_width="wrap_content"
android:layout_height="fill_parent"
android:layout_marginRight="10dp"
/>
<TextView
android:id="@+id/text"
android:layout_width="wrap_content"
android:layout_height="fill_parent"
android:textColor="#FFF"
android:textSize="5px" />
<CheckBox
android:id="@+id/checkBox1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Do Not Show Me This Again" />
</LinearLayout>
答案 0 :(得分:3)
我看到的问题是你不应该在字符串上使用==或!=。相反,使用.equals,所以它是
if( !skipMessage.equals("checked") )
答案 1 :(得分:2)
如果首选skipMessage
被“选中”,则唯一不会发生的事情是将图标设置为R.drawable.icon。将adb.show()
放入if语句中(用大括号括起来)。
if (!skipMessage.equals("checked") ) {
adb.show();
}