这是错误
TypeError:调用元类库时出错 元类冲突:派生类的元类必须是其所有基类的元类的(非严格)子类
我的models.py中有问题的课程
class Business(models.Model, forms.Form):
name = models.CharField(max_length=128)
tel_no = models.CharField(max_length=11)
address_ln1 = models.CharField(max_length=128)
address_ln2 = models.CharField(max_length=128)
city = models.CharField(max_length=64)
county = GBCountySelect()
postcode = GBPostcodeField()
website = models.URLField(max_length=128)
# Logging Info
slug = models.SlugField()
date_added = models.DateField(auto_now_add=True)
time_added = models.TimeField()
added_by_user = models.CharField(max_length=64)
last_edit_time = models.TimeField(auto_now=True)
last_edit_date = models.DateField(auto_now=True)
我收到错误的行:
name = models.CharField(max_length=128)
但我(想)这意味着这个:
class Business(models.Model, forms.Form):
我不确定它到底是什么意思,我如何从models.Model和forms.Form中继承我的模型?在创建课程时,我不能传递两个值吗?如果是这样的话?
另一个编辑
All my imports
from django.db import models
from django import forms
from django.contrib.localflavor import generic
from django.contrib.localflavor.gb.forms import GBPostcodeField, GBCountySelect
完整追溯:
Traceback (most recent call last):
File "manage.py", line 10, in <module>
execute_from_command_line(sys.argv)
File "/home/jws1000/.virtualenvs/glutenfree/lib/python2.7/site-packages/django/core/management/__init__.py", line 443, in execute_from_command_line
utility.execute()
File "/home/jws1000/.virtualenvs/glutenfree/lib/python2.7/site-packages/django/core/management/__init__.py", line 382, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File "/home/jws1000/.virtualenvs/glutenfree/lib/python2.7/site-packages/django/core/management/base.py", line 196, in run_from_argv
self.execute(*args, **options.__dict__)
File "/home/jws1000/.virtualenvs/glutenfree/lib/python2.7/site-packages/django/core/management/base.py", line 231, in execute
self.validate()
File "/home/jws1000/.virtualenvs/glutenfree/lib/python2.7/site-packages/django/core/management/base.py", line 266, in validate
num_errors = get_validation_errors(s, app)
File "/home/jws1000/.virtualenvs/glutenfree/lib/python2.7/site-packages/django/core/management/validation.py", line 30, in get_validation_errors
for (app_name, error) in get_app_errors().items():
File "/home/jws1000/.virtualenvs/glutenfree/lib/python2.7/site-packages/django/db/models/loading.py", line 158, in get_app_errors
self._populate()
File "/home/jws1000/.virtualenvs/glutenfree/lib/python2.7/site-packages/django/db/models/loading.py", line 64, in _populate
self.load_app(app_name, True)
File "/home/jws1000/.virtualenvs/glutenfree/lib/python2.7/site-packages/django/db/models/loading.py", line 88, in load_app
models = import_module('.models', app_name)
File "/home/jws1000/.virtualenvs/glutenfree/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module
__import__(name)
File "/home/jws1000/envs/glutenfree/glutenfree/glutenfree/listings/models.py", line 9, in <module>
class Business(models.Model, forms.Form):
File "/home/jws1000/.virtualenvs/glutenfree/lib/python2.7/site-packages/django/db/models/base.py", line 41, in __new__
new_class = super_new(cls, name, bases, {'__module__': module})
TypeError: Error when calling the metaclass bases
metaclass conflict: the metaclass of a derived class must be a (non-strict) subclass of the metaclasses of all its bases
答案 0 :(得分:10)
这是问题所在:
class Business(models.Model, forms.Form):
您正尝试从模型和表单继承。你不能,也不应该。
您不能因为派生类的元类必须是其所有基类的元类的(非严格)子类。表格有一个元类:
__metaclass__ = DeclarativeFieldsMetaclass
模型也有一个元类:
__metaclass__ = ModelBase
如果你这样做,你需要设置一个从这两个派生的元类。
但是,你不应该这样做,因为django有ModelForms,它可以创建模型模型,为你节省复杂的麻烦。只需停止继承Form。