Question

现在我有一些类负责保存内部存储器位图，然后列在ListViews中。

列出后，求助于一种方法，告诉您要返回的图像名称，并接收相应的位图。

当应用程序启动时，将所有需要的图像加载到内存（HashMap）中，一旦将图像从内部存储器直接加载到列表视图，该过程需要很长时间。

我正在使用视图的回收，每个项目都有两个和两个图像视图文本视图。然而，scrooll非常缓慢并且有很多滞后。

将图像存储在内存（hashmap）中是一个很好的解决方案吗？在列表时加载到内存中甚至更慢。图像有100x100像素。

我的问题是：我的延迟问题可能与图像都在内存中的事实有关？什么是最好的解决方案？

修改

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每当我滚动（列表继续），我得到这个输出。其中[]内的内容对应于位置。他经常出现0-6的位置并不奇怪吗？

修改

现在发现了一个可能的原因。

我目前是tab_activity，其中包含所有必要的视图。在xml中添加了tab_activity top_bar，其中我有一个不断被更改的图像。当图像处于自动模式（不断更改）时，选项卡内的ListView会被“重新绘制”，因此会出现延迟。

我正在使用在x时间内更改x图像的服务（音乐）。

为什么在重新绘制图像时重新绘制ListViews？

Answer 1

我不确定图片的加载是否导致延迟，但如果是，那么我建议您创建某种用户界面，向用户报告图片正在加载。（要检查图像是否导致滞后，我建议你看看DDMS只是用LogCat登录）

我使用以下代码将位图保存到内存中：

以下内容将写入内存：

public void writeBitmapToMemory(String filename, Bitmap bitmap) {
        FileOutputStream fos;
        // Use the compress method on the Bitmap object to write image to the OutputStream
        try {
            fos = game.openFileOutput(filename, Context.MODE_PRIVATE);
            // Writing the bitmap to the output stream
            bitmap.compress(Bitmap.CompressFormat.PNG, 100, fos);
            fos.close();
            // this.gameEngineLog.d(classTAG, "Bitmap successfully written: " + filename);
        } 
        catch (FileNotFoundException e) {
            e.printStackTrace();
            // this.gameEngineLog.d(classTAG, "Bitmap couldn't be written: " + filename);

        } 
        catch (IOException e) {
            e.printStackTrace();
            // this.gameEngineLog.d(classTAG, "Bitmap couldn't be written: " + filename);

        }

    }

这将从内存中读取：

public Bitmap readBitmapFromMemory(String filename) {
        Bitmap defautBitmap = null;
        File filePath = game.getFileStreamPath(filename);
        FileInputStream fi;
        try {
            fi = new FileInputStream(filePath);
            defautBitmap = BitmapFactory.decodeStream(fi);
            // this.gameEngineLog.d(classTAG, "Bitmap successfully read: " + filename);
        } 
        catch (FileNotFoundException e) {
            e.printStackTrace();
            // this.gameEngineLog.d(classTAG, "Bitmap couldn't be opened: " + filename);
        }

        return defautBitmap;

    }

存储位图的最佳方法

1 个答案: