Question

我创建了一个二维数组，我需要在该数组中搜索状态缩写，如果找到，那么我需要打印它所找到的行。我确实为此创建了一个单独的方法。我正在传递一个两个字母的州名缩写，我在我的主要内容中要求。我搜索了其他论坛，但我看到的所有问题都与此类问题无关。很多我发现的是找到重复或发现打印索引，但不是行。感谢您的帮助。

private static void ticketpayout(String state) {
    // search array for state

    //2d array with all state info
    String[][] tax = {
        {"AZ", "5%", "Annually", "$2,823,333", "After 30 Years", "$84,699,990", "Cash", "$57,050,000"},
        {"AR", "7%", "Annually", "$2,742,667", "After 30 Years", "$82,280,010", "Cash", "$55,420,000"},
        {"CO", "4%", "Annually", "$2,863,667", "After 30 Years", "$85,910,010", "Cash", "$57,865,000"},
        {"CT", "6.7%", "Annually", "$2,754,767", "After 30 Years", "$82,643,010", "Cash", "$55,664,500"},
        {"DE", "0%", "Annually", "$3,025,000", "After 30 Years", "$90,750,000", "Cash", "$61,125,000"},
        {"FL", "0%", "Annually", "$3,025,000", "After 30 Years", "$90,750,000", "Cash", "$61,125,000"},
        {"GA", "6%", "Annually", "$2,783,000", "After 30 Years", "$83,490,000", "Cash", "$56,235,000"},
        {"ID", "7.8% ", "Annually", "$2,710,400", "After 30 Years", "$81,312,000", "Cash", "$54,768,000"},
        {"IL", "5%", "Annually", "$2,823,333", "After 30 Years", "$84,699,990", "Cash", "$57,050,000"},
    };

}

Answer 1

您可以像这样搜索2D数组：

for (int i = 0; i < rowLength; i++) {
    for (int j = 0; j < colLength; j++) {
        if (tax[i][j].equals(state))
            printArray(tax, i);
    }
}

public static void printArray(String[][] array, int row) {
    for(int i = 0; i < rowLength; i++)
        System.out.print(array[row][i] + " "); 
}

要回答@ Tree的问题，请检查两行是否相等：

public static boolean rowEquals(String[] one, String[] two) {
    for(int i = 0; i < one.length; i++)
        if(!one[i].equals(two[i]))
            return false;
    return true;
}

Answer 2

要直接回答您的问题，您可以遍历tax数组，检查每个元素，如下所示;

private static String[][] tax = ...;

private static String[] ticketpayout(String state) {
    for (String[] taxRow : tax) {
        if (taxRow[0].equals(state)) {
            return taxRow;
        }
    }

    return null;
}

但是，我不认为这是你想要解决的问题的最佳类设计。最好从这里的数据中创建一个对象，并根据状态缩写将它们添加到Map中，如下所示：

public class TaxInfo {
    String state;
    double taxRate;
    Period period;
    etc...

    enum Period {
        ANNUALLY,
        MONTHLY,
        etc...
    }
}

private static Map<String, TaxInfo> tax = new HashMap<String, TaxInfo>();

private static void populateTaxInfo() {
    tax.put("AZ", new TaxInfo("AZ", 5, TaxInfo.Period.ANNUALLY, ...));
    tax.put("AR", new TaxInfo("AR", 7, TaxInfo.Period.ANNUALLY, ...));
    tax.put("CO", new TaxInfo("CO", 4, TaxInfo.Period.ANNUALLY, ...));
    ...
}

然后检索记录，只需例如tax.get("AZ");

Answer 3

您需要搜索[0] [1] [0] [2] ..等等，直到找到您正在寻找的内容...

你可以做嵌套for循环。也搜索这个网站，我确定有搜索示例。

您还应该发布您尝试过的内容，以便我们为您提供帮助。

search a 2 dimensional array in java

在2d数组（Java）中搜索元素

3 个答案: