ListView如何使用onClick打开一个新活动?

时间:2012-07-25 04:12:51

标签: android string listview apk

大家好。我的目标是当我想点击ListView中的特定项目时,它会打开我编程的新活动。例如:当我点击“João”时,我希望它打开一个名为Joao的课程。我尝试过使用简单的代码,但它不起作用。当我从ListView点击João的名字时没有任何反应。

这是我正在使用的代码:

public class Searchsort extends Activity {

    private ListView lv1;
    private EditText ed;
    private String lv_arr[]={"John","Mary","Carl","Rose","Charlie","Allan", "João"};
    private ArrayList<String> arr_sort= new ArrayList<String>();
    int textlength=0;

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle icicle) {
        super.onCreate(icicle);
        setContentView(R.layout.main);
        lv1 = (ListView)findViewById(R.id.ListView01);
        ed = (EditText)findViewById(R.id.EditText01);

        // By using setAdpater method in listview we an add string array in list.

        lv1.setAdapter(new ArrayAdapter<String>(this,android.R.layout.simple_list_item_1 ,   lv_arr));
        ed.addTextChangedListener(new TextWatcher() {

            public void afterTextChanged(Editable s) {

            }

            public void beforeTextChanged(CharSequence s, int start, int count, int after) {

            }

            public void onTextChanged(CharSequence s, int start, int before, int count) {
                textlength=ed.getText().length();
                arr_sort.clear();
                for(int i=0;i<lv_arr.length;i++) {
                    if(textlength<=lv_arr[i].length()) {
                        if(ed.getText().toString().equalsIgnoreCase((String) lv_arr[i].subSequence(0,  textlength))) {
                            arr_sort.add(lv_arr[i]);
                        }
                    }
                }

                lv1.setAdapter(new ArrayAdapter<String>  (Searchsort.this,android.R.layout.simple_list_item_1 , arr_sort));

            }
        });
    }

    public void onListItemClick(ListView parent, View v, int position, long id) {
        if ("João".equals(lv_arr[position])) { 
            Intent myIntent = new Intent(Searchsort.this, Joao.class);
            startActivity(myIntent);
        }
    }

}

5 个答案:

答案 0 :(得分:0)

lv1.setOnItemClickListener(new OnItemClickListener() {
  public void onItemClick(AdapterView<?> parent, View view, int position, long id) {

       Intent intent = new Intent(Searchsort.this, Joao.class);                                                  

                    startActivity(intent);          
                }
            }        
        });

答案 1 :(得分:0)

setOnItemClickListener使用ListView并处理那里的活动。

答案 2 :(得分:0)

请检查您的Androidmanifest.xml

添加声明如:

<activity android:name=".CLASS_NAME"> </activity>

您必须声明所有活动。

答案 3 :(得分:0)

正如Niko Suggested以下列方式使用setOnItemClickListener()。

public class Searchsort extends Activity {

private ListView lv1;
private EditText ed;
private String lv_arr[]={"John","Mary","Carl","Rose","Charlie","Allan", "João"};
private ArrayList<String> arr_sort= new ArrayList<String>();
int textlength=0;
private String getItem;

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle icicle) {
    super.onCreate(icicle);
    setContentView(R.layout.main);
    lv1 = (ListView)findViewById(R.id.listView1);
    ed = (EditText)findViewById(R.id.EditText01);

    // By using setAdpater method in listview we an add string array in list.

    lv1.setAdapter(new ArrayAdapter<String>(this,android.R.layout.simple_list_item_1 , lv_arr));
    // Here I have set Listener for listview 
    lv1.setOnItemClickListener(new OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> arg0, View arg1, int arg2,
                long arg3) {
            // TODO Auto-generated method stub
 // Here I am getting the selected item of listview.
            getItem = (arg0.getItemAtPosition(arg2).toString());

            if(getItem.equals("John"))
            {
                Intent i = new Intent(Searchsort.this,John.class);
                startActivity(i);
            }
        }
    });
    ed.addTextChangedListener(new TextWatcher() {
        public void afterTextChanged(Editable s) {
        }

        public void beforeTextChanged(CharSequence s, int start, int count, int after) {

        }

        public void onTextChanged(CharSequence s, int start, int before, int count) {
            textlength=ed.getText().length();
            arr_sort.clear();
            for(int i=0;i<lv_arr.length;i++) {
                if(textlength<=lv_arr[i].length()) {
                    if(ed.getText().toString().equalsIgnoreCase((String) lv_arr[i].subSequence(0,  textlength))) {
                        arr_sort.add(lv_arr[i]);
                    }
                }
            }
            lv1.setAdapter(new ArrayAdapter<String>  (Searchsort.this,android.R.layout.simple_list_item_1 , arr_sort));
        }
    });
}    
 }

答案 4 :(得分:0)

试试这个..

listView.setOnItemClickListener(new OnItemClickListener() {
        public void onItemClick(AdapterView<?> parent, View view,
            int position, long id) {

if(position == 1)
{

         Intent myIntent = new Intent(YourActivity.this, SecondActivity.class);
             startActivityForResult(myIntent, 0);
}

if(position == 2)
{

         Intent myIntent =  new Intent(YourActivity.this, ThirdActivity.class);
             startActivityForResult(myIntent, 0);
}
    }
  });

希望这会对你有所帮助: - )