请不要使用lamba回复。我找到了类似的线程,但仍然需要帮助。
我正在尝试显示employees表中不是当前所选经理员工的姓名。
我的两个sql表的结构如下,但这是假数据
Employees:
pk name
1 bob
2 sam
3 greg
4 kip
5 jill
6 kelly
7 chris
ExpenseTeamMembers:
pk expMgrPk empPk
1 7 2
2 7 5
3 7 1
4 3 6
5 3 4
因此,如果当前选择的(mgr变量)为3,我想获取employees表中除了6,4之外的所有empPks的名称。(kelly,kip)现在unselectedEmps = sam,jill,bob而不是employees表中的所有其他5个名称。
var unselectedEmps = (from u in db.employees
join o in db.expenseTeamMembers on u.pk equals o.empPk
where o.expMgrPk != mgr
select u.name).ToList();
lstAvailable.DataSource = unselectedEmps;
答案 0 :(得分:1)
问题在于,当您实际需要左外连接
时,您正在进行内连接答案 1 :(得分:1)
经过我们的扩展讨论,我认为你想要的是这个。
from u in db.Employees
where !(from e in db.ExpenseTeamMembers
where e.expMgrPk == selectedMgr.pk
select e.empPk).Contains(u.pk)
select u.Name
答案 2 :(得分:1)
我尝试了以下内容,它提供了正确的输出。请试一试:
List<Employees> emps = new List<Employees>();
emps.Add(new Employees { PK = 1, Name = "bob" });
emps.Add(new Employees { PK = 2, Name = "sam" });
emps.Add(new Employees { PK = 3, Name = "greg" });
emps.Add(new Employees { PK = 4, Name = "kip" });
emps.Add(new Employees { PK = 5, Name = "jill" });
emps.Add(new Employees { PK = 6, Name = "kelly" });
emps.Add(new Employees { PK = 7, Name = "chris" });
List<ExpenseTeamMembers> etm = new List<ExpenseTeamMembers>();
etm.Add(new ExpenseTeamMembers { empPK = 2, ExpMgrPK = 7, PK = 1 });
etm.Add(new ExpenseTeamMembers { empPK = 5, ExpMgrPK = 7, PK = 2 });
etm.Add(new ExpenseTeamMembers { empPK = 1, ExpMgrPK = 7, PK = 3 });
etm.Add(new ExpenseTeamMembers { empPK = 6, ExpMgrPK = 3, PK = 4 });
etm.Add(new ExpenseTeamMembers { empPK = 4, ExpMgrPK = 3, PK = 5 });
var query = from t in
(
from emp in emps
join o in etm on emp.PK equals o.empPK into j
from k in j.DefaultIfEmpty()
select new { Name = k == null ? string.Empty : emp.Name })
where t.Name != string.Empty
select t.Name;