以下是基于Implement a Range Adaptor with arguments的范围适配器示例:
#include <boost/range/join.hpp>
#include <boost/range/algorithm.hpp>
#include <boost/range/adaptors.hpp>
#include <boost/range/iterator_range.hpp>
#include <boost/iterator/permutation_iterator.hpp>
#include <vector>
#include <list>
#include <iterator>
#include <iostream>
template <typename Range, typename Index>
class permutation_range :
public boost::iterator_range<
boost::permutation_iterator<
typename boost::range_iterator<Range>::type,
typename boost::range_iterator<Index>::type>>
{
using value_type = typename boost::range_value<Range>::type;
using replaced_iterator = boost::permutation_iterator<
typename boost::range_iterator<Range>::type,
typename boost::range_iterator<Index>::type>;
using base_t = boost::iterator_range<replaced_iterator>;
public:
permutation_range(Range& r, Index& i)
: base_t(replaced_iterator(boost::begin(r), boost::begin(i)),
replaced_iterator(boost::end(r), boost::end(i)))
{}
};
template <typename Range, typename Index>
permutation_range<Range, Index>
permutation(Range& r, Index& i)
{
return permutation_range<Range, Index>(r, i);
}
int main()
{
std::vector<int> v1{99, 1, 99, 2, 99, 3};
std::list<int> indexer{1, 3, 5};
boost::copy(permutation(v1, indexer),
std::ostream_iterator<int>(std::cout, " "));
}
输出
1 2 3
我想调整上述内容以使用boost::joined_range。换句话说,取两个向量,然后将它们连接到permutation_range
内的一个更长的范围内。这个想法很简单:
示例会输出2 4 6
:
int main()
{
std::vector<int> v1{1, 2, 3};
std::vector<int> v2{4, 5, 6};
std::list<int> indexer{1, 3, 5};
boost::copy(permutation(v1, v2, indexer),
std::ostream_iterator<int>(std::cout, " "));
}
到目前为止,我所有的尝试都以一大堆编译器错误结束,我没有展示过这些尝试,因为我可能会离开。我不知道是否有可能,但有人可以帮助我吗?
最终编辑(解决方案有点破解,以便在基类之前初始化范围)
#include <boost/range/join.hpp>
#include <boost/range/algorithm.hpp>
#include <boost/range/adaptors.hpp>
#include <boost/range/iterator_range.hpp>
#include <boost/iterator/permutation_iterator.hpp>
#include <vector>
#include <list>
#include <iterator>
#include <iostream>
template <typename R1, typename R2>
struct initialize_me_first
{
initialize_me_first(typename boost::range::joined_range<const R1, const R2> j)
: j_range(j)
{}
typename boost::range::joined_range<const R1, const R2> j_range;
};
template <typename Range1, typename Range2, typename Index>
class permutation_range :
public initialize_me_first<Range1, Range2>,
public boost::iterator_range<
boost::permutation_iterator<
typename boost::range_iterator<
boost::range::joined_range<Range1, Range2>>::type,
typename boost::range_iterator<Index>::type>>
{
using value_type = typename boost::range_value<Range1>::type;
using replaced_iterator = boost::permutation_iterator<
typename boost::range_iterator<
boost::range::joined_range<Range1, Range2>>::type,
typename boost::range_iterator<Index>::type>;
using base_t = boost::iterator_range<replaced_iterator>;
using init = initialize_me_first<Range1, Range2>;
public:
permutation_range(const Range1& r1, const Range2& r2, const Index& i)
: init(boost::join(r1, r2)),
base_t(replaced_iterator(boost::begin(init::j_range),
boost::begin(i)),
replaced_iterator(boost::end(init::j_range),
boost::end(i)))
{}
};
template <typename Range1, typename Range2, typename Index>
permutation_range<const Range1, const Range2, const Index>
permutation(const Range1& r1, const Range2& r2, const Index& i)
{
return permutation_range<const Range1,
const Range2,
const Index>(r1, r2, i);
}
int main()
{
std::vector<int> v1{1, 2, 3};
std::vector<int> v2{4, 5, 6};
std::list<int> indexer{1, 3, 5};
boost::copy(permutation(v1, v2, indexer),
std::ostream_iterator<int>(std::cout, " "));
}
答案 0 :(得分:2)
要加入两个范围,请使用boost::join
:
#include <boost/range/join.hpp>
boost::copy(permutation(boost::join(v1, v2), indexer), ...
但是改变你的Range
参数要通过const引用传递而不是非const引用。没有理由要求这些参数的可修改版本,因为您实际上并未对其内容进行置换。