Question

我的问题是，如何在变量中存储日期，然后推送新日期。我会解释我的代码： - 记住今天的日期，并从文件的最后写入时间中减去它 - 小时数 - 最后写入时间大于或等于1小时通知编辑文件 - 最近的写作时间 - 然后睡10秒

问题是，即使我编辑文件，循环仍然显示上一个日期。我怎样才能使它工作？

$file = get-childitem $input_users
   $time = (get-date)-$file.lastwritetime
   $hours = $time.hours

   while (($time.hours) -ge (1)){
         write-host -BackgroundColor DarkRed -ForegroundColor White  "$input was written to $hours hours ago, please edit it first"
         write-host -BackgroundColor DarkRed -ForegroundColor White  "Next check in 10 seconds."
         $time = (get-date)-$file.lastwritetime
                                }

Answer 1

您需要获取一个新文件对象并重新计算循环内的小时数：

$file = get-childitem $input_users
$time = (get-date)-$file.lastwritetime
$hours = $time.hours

while (($time.hours) -ge (1)){
    write-host -BackgroundColor DarkRed -ForegroundColor White  "$input was written to $hours hours ago, please edit it first"
    write-host -BackgroundColor DarkRed -ForegroundColor White  "Next check in 10 seconds."
    $file = Get-ChildItem $input_users
    $time = (Get-Date) - $file.LastWriteTime

}

Powershell - 在变量中刷新日期

1 个答案: