Question

您好我有一张状态栏表。如何使用SQL获取记录总数，具有通过状态的记录总数和具有失败状态的记录总数？

Answer 1

这样的事情怎么样：

SELECT Status, COUNT(*)
FROM dbo.YourTable
GROUP BY Status WITH ROLLUP

如果这两种状态（通过，失败）是唯一的状态（否则你还需要WHERE Status IN ('fail', 'pass')条件），这将有效 - 而WITH ROLLUP也会给你总数所有状态的行（输出中带有Status = NULL）

Answer 2

我会写一个类似于

的查询

select 
Count(*) as TotalRecords, 
Sum(case where status = 'Pass' then 1 else 0 end) as PassRecords,
Sum(case where status = 'Fail' then 1 else 0 end) as FaileRecords
from Table

Answer 3

您可以使用案例陈述和汇总来执行此操作：

select count(*), sum(case when status = 'pass' then 1 else 0 end) as pass,
       sum(case when status = 'fail' then 1 else 0 end) as fail
from t

Answer 4

其他几种选择（SQL Server 2008 +）：

DECLARE @foo TABLE([status] CHAR(4));

INSERT @foo SELECT 'pass'
UNION ALL SELECT 'pass'
UNION ALL SELECT 'fail';

-- option #1:

SELECT [status], c = COUNT(*)
FROM @foo
GROUP BY GROUPING SETS(([status]), ());

-- option #2:

SELECT [status], c = COUNT(*)
FROM @foo
GROUP BY [status]
UNION ALL 
SELECT NULL, COUNT(*) OVER() FROM @foo;

选择查询以获取SQL Server中的总记录数

4 个答案: