我在名为SegmentedAnswer的视图中有一个UISegmentedControl,有四个段。 有没有办法以编程方式更改段数? 非常感谢!
答案 0 :(得分:120)
是的,您可以使用
removeSegmentAtIndex:(NSUInteger) animated:(BOOL)
和
insertSegmentWithTitle:(NSString *) atIndex:(NSUInteger) animated:(BOOL)
答案 1 :(得分:42)
要完全替换细分,您可以使用以下功能:
- (void)setSegments:(NSArray *)segments
{
[segmentController removeAllSegments];
for (NSString *segment in segments) {
[segmentController insertSegmentWithTitle:segment atIndex:segmentController.numberOfSegments animated:NO];
}
}
希望这会有所帮助。
答案 2 :(得分:17)
这里有一个小的Swift扩展来用新值数组替换当前的segmentedControl
extension UISegmentedControl {
func replaceSegments(segments: Array<String>) {
self.removeAllSegments()
for segment in segments {
self.insertSegmentWithTitle(segment, atIndex: self.numberOfSegments, animated: false)
}
}
}
extension UISegmentedControl {
func replaceSegments(segments: Array<String>) {
self.removeAllSegments()
for segment in segments {
self.insertSegment(withTitle: segment, at: self.numberOfSegments, animated: false)
}
}
}
答案 3 :(得分:3)
这是一个用一系列字符串替换段的Swift扩展。它类似于此处给出的another answer,除了它可以与任何序列一起使用,这意味着你也可以传入切片,集合等。
extension UISegmentedControl {
/// Replace the current segments with new ones using a given sequence of string.
/// - parameter withTitles: The titles for the new segments.
public func replaceSegments<T: Sequence>(withTitles: T) where T.Iterator.Element == String {
removeAllSegments()
for title in withTitles {
insertSegment(withTitle: title, at: numberOfSegments, animated: false)
}
}
}
答案 4 :(得分:2)
为了完整起见(因为我最终在这里寻找如何在xib中实现相同的东西),这里是如何在xib中实现的:
答案 5 :(得分:0)
为我工作,UIsegmentedControll包含两个段,我想在索引2中添加一个,在swift 2.2中使用此代码使用:
SEG_TipoFiltro.insertSegmentWithTitle("Title", atIndex: 2, animated: false)
答案 6 :(得分:0)
使用代码在swift4中添加和删除细分
class ViewController: UIViewController {
@IBOutlet weak var segment1: UISegmentedControl!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
}
@IBAction func insert(_ sender: Any) {
segment1.insertSegment(withTitle: "\(segment1.numberOfSegments+1)", at: segment1.numberOfSegments, animated: true)
}
@IBAction func remove(_ sender: Any) {
segment1.removeSegment(at: segment1.numberOfSegments-1, animated: true)
}
}