Question

请按照示例xml中的注释解释我需要的所有内容，它在输出xml中以相同的顺序检查每个scenerio三个scenerio。

输入XML

   <!-- In the below xml there will be one ASNInDesc with multiple ASNInPO's 
        and each ASNInPO contains one ASNInCtn and each ASNInCtn contains one ASNInItem -->

<ASNInDesc>
   <asn_nbr>ASN-1</asn_nbr>

   <!-- In the below two ASNInPO's po_nbr is same container_id under ASNInCtn is same and item_id under
        ASNInItem is same. In this case two ASNInPO's has to be merged and two ASNInCtn's has to be merged
        into one tag(since the container_id is same) and two ASNInItem's has to be merged into one tag and unit_qty is to be added  -->

   <ASNInPO>
      <po_nbr>PO-1</po_nbr>
      <ASNInCtn>
         <container_id>CONTAINER-1</container_id>
         <ASNInItem>
            <item_id>ITEM-1</item_id>
            <unit_qty>2</unit_qty>
         </ASNInItem>
      </ASNInCtn>
   </ASNInPO>
   <ASNInPO>
      <po_nbr>PO-1</po_nbr>
      <ASNInCtn>
         <container_id>CONTAINER-1</container_id>
         <ASNInItem>
            <item_id>ITEM-1</item_id>
            <unit_qty>2</unit_qty>
         </ASNInItem>
      </ASNInCtn>
   </ASNInPO>

   <!-- In the below two ASNInPO's po_nbr is same container_id under ASNInCtn is same and item_id under
        ASNInItem is different. In this case two ASNInPO's has to be merged and two ASNInCtn's has to be merged into one tag and
        two different ASNInItem's for the two different items  -->

    <ASNInPO>
      <po_nbr>PO-2</po_nbr>
      <ASNInCtn>
         <container_id>CONTAINER-2</container_id>
         <ASNInItem>
            <item_id>ITEM-2</item_id>
            <unit_qty>3</unit_qty>
         </ASNInItem>
      </ASNInCtn>
   </ASNInPO>
   <ASNInPO>
      <po_nbr>PO-2</po_nbr>
      <ASNInCtn>
         <container_id>CONTAINER-2</container_id>
         <ASNInItem>
            <item_id>ITEM-3</item_id>
            <unit_qty>3</unit_qty>
         </ASNInItem>
      </ASNInCtn>
   </ASNInPO>

   <!-- In the below two ASNInPO's po_nbr is same container_id under ASNInCtn is different and item_id under
        ASNInItem is different. In this case two ASNInPO's has to be merged into one tag with
        two different ASNInCtn's each having their own ASNInItem  -->

   <ASNInPO>
      <po_nbr>PO-3</po_nbr>
      <ASNInCtn>
         <container_id>CONTAINER-3</container_id>
         <ASNInItem>
            <item_id>ITEM-3</item_id>
            <unit_qty>2</unit_qty>
         </ASNInItem>
      </ASNInCtn>
   </ASNInPO>
   <ASNInPO>
      <po_nbr>PO-3</po_nbr>
      <ASNInCtn>
         <container_id>CONTAINER-4</container_id>
         <ASNInItem>
            <item_id>ITEM-3</item_id>
            <unit_qty>2</unit_qty>
         </ASNInItem>
      </ASNInCtn>
   </ASNInPO>

</ASNInDesc>

输出XML

<?xml version = '1.0' encoding = 'UTF-8'?>
<ASNInDesc>
   <asn_nbr>ASN-1</asn_nbr>
  <!-- Scenerio-1 --> 
   <ASNInPO>
      <po_nbr>PO-1</po_nbr>
      <ASNInCtn>
         <container_id>CONTAINER-1</container_id>
         <ASNInItem>
            <item_id>ITEM-1</item_id>
            <unit_qty>4</unit_qty>
         </ASNInItem>        
      </ASNInCtn>
  </ASNInPO>
  <!-- Scenerio-2 -->  
  <ASNInPO>
      <po_nbr>PO-2</po_nbr>
      <ASNInCtn>
         <container_id>CONTAINER-2</container_id>
         <ASNInItem>
            <item_id>ITEM-2</item_id>
            <unit_qty>3</unit_qty>
         </ASNInItem>
         <ASNInItem>
            <item_id>ITEM-3</item_id>
            <unit_qty>3</unit_qty>
         </ASNInItem>        
      </ASNInCtn>
   </ASNInPO>
  <!-- Scenerio-3 -->   
   <ASNInPO>
      <po_nbr>PO-3</po_nbr>
      <ASNInCtn>
         <container_id>CONTAINER-3</container_id>
         <ASNInItem>
            <item_id>ITEM-3</item_id>
            <unit_qty>2</unit_qty>
         </ASNInItem>
      </ASNInCtn>
      <ASNInCtn>
         <container_id>CONTAINER-4</container_id>
         <ASNInItem>
            <item_id>ITEM-3</item_id>
            <unit_qty>2</unit_qty>
         </ASNInItem>
      </ASNInCtn>     
   </ASNInPO>

我尝试过自己的xsl，但无法处理所有的场景。请帮我解决这个问题。在此先感谢。

Answer 1

这是使用Muenchian grouping的XSLT 1.0样式表。这是基于您对其他问题的my answer。

这是相同的方法，但是使用调整后的键，我们使用元素自己的id和父元素的id的串联来查找元素以进行分组。例如，使用以下连接密钥查找ASNInItem个元素：concat(../../po_nbr, '|', ../container_id, '|', item_id)。分隔符的选择并不重要，但您需要选择一个未出现在ID中的字符。

此外，还增加了单位数量的总和。

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" 
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output method="xml" indent="yes" encoding="UTF-8"/>

  <xsl:key name="ASNInPO" match="ASNInPO" 
           use="po_nbr"/>

  <xsl:key name="ASNInCtn" match="ASNInCtn" 
           use="concat(../po_nbr, '|', 
                       container_id)"/>

  <xsl:key name="ASNInItem" match="ASNInItem" 
           use="concat(../../po_nbr, '|', 
                       ../container_id, '|', 
                       item_id)"/>

  <xsl:template match="ASNInDesc">
    <xsl:copy>
      <xsl:copy-of select="asn_nbr"/>
      <xsl:apply-templates 
          select="ASNInPO[generate-id() =
                          generate-id(key('ASNInPO', 
                                          po_nbr)[1])]"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="ASNInPO">
    <xsl:copy>
      <xsl:copy-of select="po_nbr"/>
      <xsl:apply-templates 
          select="key('ASNInPO', po_nbr)/
                  ASNInCtn[generate-id() =
                           generate-id(key('ASNInCtn',
                                           concat(../po_nbr, '|', 
                                                  container_id))[1])]"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="ASNInCtn">
    <xsl:copy>
      <xsl:copy-of select="container_id"/>
      <xsl:apply-templates
          select="key('ASNInCtn',
                      concat(../po_nbr, '|', 
                             container_id))/
                  ASNInItem[generate-id() =
                            generate-id(key('ASNInItem', 
                                        concat(../../po_nbr, '|',
                                               ../container_id, '|',
                                               item_id))[1])]"/>
    </xsl:copy>
  </xsl:template>


  <xsl:template match="ASNInItem">
    <xsl:copy>
      <xsl:copy-of select="item_id"/>
      <unit_qty>
        <xsl:value-of 
            select="sum(key('ASNInItem', 
                        concat(../../po_nbr, '|', 
                               ../container_id, '|', 
                               item_id))/unit_qty)"/>
      </unit_qty>
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

将节点分组为三个级别并对一个节点求和

1 个答案: