Question

我有一个零件表，我有5个字段。我想要显示mfgpn的QTY，同时显示其他3个字段的第一个返回行（Manfucturer，DateCode，Description）。我最初想到如下使用MIN函数，但这并不能真正帮助我，因为数据不是int数据类型。我该怎么做呢？现在我坚持下面的查询：

SELECT SUM([QTY]) AS QTY
  ,[MFGPN]
  ,MIN([MANUFACTURER]) AS MANUFACTURER
  ,MIN([DATECODE]) AS DateCode
  ,MIN([DESCRIPTION]) AS DESCRIPTION
  INTO part
GROUP BY MFGPN, MANUFACTURER, DATECODE, description
ORDER BY mfgpn ASC

Answer 1

CROSS APPLY会为你效力吗？

SELECT 
    SUM(a.[QTY]) AS QTY
    ,a.[MFGPN]
    ,c.[MANUFACTURER]
    ,c.[DATECODE]
    ,c.[DESCRIPTION]
FROM part a
    CROSS APPLY (SELECT TOP 1 * FROM part b WHERE a.[MFGPN] = b.[MFGPN]) c
GROUP BY 
    a.[MFGPN]
    ,c.[MANUFACTURER]
    ,c.[DATECODE]
    ,c.[DESCRIPTION]

测试以下内容：

DECLARE @T1 AS TABLE (
    [QTY] int
    ,[MFGPN] NVARCHAR(50)
    ,[MANUFACTURER] NVARCHAR(50)
    ,[DATECODE] DATE
    ,[DESCRIPTION] NVARCHAR(50));

INSERT @T1 VALUES
(2, 'MFGPN-1', 'MANUFACTURER-A', '20120101', 'A-1'),
(4, 'MFGPN-1', 'MANUFACTURER-B', '20120102', 'B-1'),
(3, 'MFGPN-1', 'MANUFACTURER-C', '20120103', 'C-1'),
(1, 'MFGPN-2', 'MANUFACTURER-A', '20120101', 'A-2'),
(5, 'MFGPN-2', 'MANUFACTURER-B', '20120101', 'B-2')

SELECT 
    SUM(a.[QTY]) AS QTY
    ,a.[MFGPN]
    ,c.[MANUFACTURER]
    ,c.[DATECODE]
    ,c.[DESCRIPTION]
FROM @T1 a
    CROSS APPLY (SELECT TOP 1 * FROM @T1 b WHERE a.[MFGPN] = b.[MFGPN]) c
GROUP BY 
    a.[MFGPN]
    ,c.[MANUFACTURER]
    ,c.[DATECODE]
    ,c.[DESCRIPTION]

可生产

QTY MFGPN   MANUFACTURER    DATECODE    DESCRIPTION
9   MFGPN-1 MANUFACTURER-A  2012-01-01  A-1
6   MFGPN-2 MANUFACTURER-A  2012-01-01  A-2

Answer 2

可以使用windowed SUM()：

轻松管理

WITH summed_and_ranked AS (
  SELECT
    MFGPN,
    MANUFACTURER,
    DATECODE,
    DESCRIPTION,
    QTY = SUM(QTY) OVER (PARTITION BY MFGPN),
    RNK = ROW_NUMBER() OVER (
      PARTITION BY MFGPN
      ORDER BY DATECODE  -- or which column should define the order?
    )
  FROM atable
)
SELECT
  MFGPN,
  MANUFACTURER,
  DATECODE,
  DESCRIPTION,
  QTY,
INTO parts
FROM summed_and_ranked
WHERE RNK = 1
;

对于每一行，计算组中的总组数量和排名。当实际获取要插入新表的行（主SELECT）时，只会提取RNK值为1的行。因此，您将获得包含组总计的结果集以及某些行的详细信息。

SQL Group BY SUM一列并选择第一行的分组项

2 个答案: