这里有一个简单的看看我有的表
正如您所看到的,目录表是一个自引用表,因此可以从0开始递归它,这是假的“根”类别(也可以是null,但它不是)。
示例数据:
1, Apples, 0
5, Yummy, 1
10, Really Yummy, 5
15, Yucky, 0
18, Some Sub Cat, 15
20, Some Deep Sub Cat, 18
25, Some Deep Sub Cat 2, 18
最深的任何类别层次结构都可以是4深,我正在尝试获得如下所示的输出:
CatId, [up to 4 deep of category names on the hierarchy in separate columns, or null if none]
1, Apples, NULL, NULL, NULL
5, Apples, Yummy, NULL, NULL
10, Apples, Yummy, Really Yummy, NULL
15, Apples, Yucky, NULL, NULL
18, Apples, Yucky, Some Sub Cat, NULL
20, Apples, Yucky, Some Sub Cat, Some Deep Sub Cat
25, Apples, Yucky, Some Sub Cat, Some Deep Sub Cat 2
这个SQL很接近,但是它向后生成,左对齐
select c1.categoryid, c1.name, c2.name, c3.name, c4.name
from category c1
left outer join category c2
on c1.parentcategoryid = c2.categoryid
left outer join category c3
on c2.parentcategoryid = c3.categoryid
left outer join category c4
on c3.parentcategoryid = c4.categoryid
任何SQL天才都有一些好主意吗?
答案 0 :(得分:1)
select c1.CategoryId as id,
c1.CategoryName as n1,
c2.CategoryName as n2,
c3.CategoryName as n3,
c4.CategoryName as n4
from Category c1
left outer join Category c2 on c2.ParentCategoryId = c1.CategoryId
left outer join Category c3 on c3.ParentCategoryId = c2.CategoryId
left outer join Category c4 on c4.ParentCategoryId = c3.CategoryId
where c1.parentcategoryid = 0;
(根据您的编辑:您刚刚在联接中翻转了ParentCategoryId和CategoryID。)