汇总/递归添加SQL Server 2008

时间:2012-07-23 13:56:57

标签: sql sql-server-2008 tsql

我有一个查询with rollup,可以输出数据(查询有点忙,但我可以在必要时发布)

range    subCounts    Counts    percent
1-9      3            100       3.0
10-19    13           100       13.0
20-29    30           100       33.0
30-39    74           100       74.0
NULL     100          100       100.0

如何保持总计percent的总和?假设我需要找到底部的15个百分位,在这种情况下3+13=16所以我希望最后一行返回读取

range    subCounts    counts    percent
10-19    13           100       13.0

EDIT1:此处是查询

select '$'+cast(+bin*10000 + ' ' as varchar(10)) + '-' + cast(bin*10000+9999 as varchar(10)) as bins, 
    count(*) as numbers,
    (select count(distinct patient.patientid) from patient 
    inner join tblclaims on patient.patientid = tblclaims.patientid
    and patient.admissiondate = tblclaims.admissiondate
    and patient.dischargedate = tblclaims.dischargedate
    inner join tblhospitals on tblhospitals.hospitalnpi = patient.hospitalnpi
    where (tblhospitals.hospitalname = 'X') 
    ) as Totals
    , round(100*count(*)/cast((select count(distinct patient.patientid) from patient 
    inner join tblclaims on patient.patientid = tblclaims.patientid
    and patient.admissiondate = tblclaims.admissiondate
    and patient.dischargedate = tblclaims.dischargedate
    inner join tblhospitals on tblhospitals.hospitalnpi = patient.hospitalnpi
    where (tblhospitals.hospitalname = 'X')) as float),2) as binsPercent


from
(

select tblclaims.patientid, sum(claimsmedicarepaid) as TotalCosts, 
    cast(sum(claimsmedicarePaid)/10000 as int) as bin
    from tblclaims inner join patient on patient.patientid = tblclaims.patientid
    and patient.admissiondate = tblclaims.admissiondate 
    and patient.dischargedate = tblclaims.dischargedate
    inner join tblhospitals on patient.hospitalnpi = tblhospitals.hospitalnpi
    where tblhospitals.hospitalname = 'X'
    group by tblclaims.patientid
)   as t 
group by bin with rollup

2 个答案:

答案 0 :(得分:0)

好的,所以对于任何可能使用它作为参考的人我都知道我需要做什么。

我在查询中添加了row_number() over(bin) as rownum并将所有内容保存为视图。

然后我用了

SELECT *,
          SUM(t2.binspercent) AS SUM
FROM t t1
INNER JOIN t t2 ON t1.rownum >= t2.rownum
GROUP BY t1.rownum,
         t1.bins, t1.numbers, t1.uktotal, t1.binspercent
ORDER BY t1.rownum

通过加入t1.rownum> = t2.rownum,您可以得到滚动计数的东西。

答案 1 :(得分:0)

这不是我想要的,但它在同一条轨道上: http://blog.tallan.com/2011/12/08/sql-server-2012-windowing-functions-part-1-of-2-running-and-sliding-aggregates/http://blog.tallan.com/2011/12/19/sql-server-2012-windowing-functions-part-2-of-2-new-analytic-functions/ - 请查看PERCENT_RANK CUME_DIST PERCENTILE_CONT PERCENTILE_DISC

抱歉蹩脚的回答