我正在使用d3.js树,并且想要动态添加节点,而不是预先加载整个树。
如何在单击节点时动态添加其他JSON节点,以修改以下内容? (见下面的链接,以及下面的代码)
http://mbostock.github.com/d3/talk/20111018/tree.html
因此,不是预加载整个树,而是仅在单击父级时才检索子节点。我可以在toggle函数中检索子节点的json,但是我无法弄清楚如何将它们添加到树中。
var m = [20, 120, 20, 120],
w = 1280 - m[1] - m[3],
h = 800 - m[0] - m[2],
i = 0,
root;
var tree = d3.layout.tree()
.size([h, w]);
var diagonal = d3.svg.diagonal()
.projection(function(d) { return [d.y, d.x]; });
var vis = d3.select("#body").append("svg:svg")
.attr("width", w + m[1] + m[3])
.attr("height", h + m[0] + m[2])
.append("svg:g")
.attr("transform", "translate(" + m[3] + "," + m[0] + ")");
d3.json("flare.json", function(json) {
root = json;
root.x0 = h / 2;
root.y0 = 0;
function toggleAll(d) {
if (d.children) {
d.children.forEach(toggleAll);
toggle(d);
}
}
// Initialize the display to show a few nodes.
root.children.forEach(toggleAll);
toggle(root.children[1]);
toggle(root.children[1].children[2]);
toggle(root.children[9]);
toggle(root.children[9].children[0]);
update(root);
});
function update(source) {
var duration = d3.event && d3.event.altKey ? 5000 : 500;
// Compute the new tree layout.
var nodes = tree.nodes(root).reverse();
// Normalize for fixed-depth.
nodes.forEach(function(d) { d.y = d.depth * 180; });
// Update the nodes…
var node = vis.selectAll("g.node")
.data(nodes, function(d) { return d.id || (d.id = ++i); });
// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter().append("svg:g")
.attr("class", "node")
.attr("transform", function(d) { return "translate(" + source.y0 + "," + source.x0 + ")"; })
.on("click", function(d) { toggle(d); update(d); });
nodeEnter.append("svg:circle")
.attr("r", 1e-6)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });
nodeEnter.append("svg:text")
.attr("x", function(d) { return d.children || d._children ? -10 : 10; })
.attr("dy", ".35em")
.attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })
.text(function(d) { return d.name; })
.style("fill-opacity", 1e-6);
// Transition nodes to their new position.
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; });
nodeUpdate.select("circle")
.attr("r", 4.5)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });
nodeUpdate.select("text")
.style("fill-opacity", 1);
// Transition exiting nodes to the parent's new position.
var nodeExit = node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.remove();
nodeExit.select("circle")
.attr("r", 1e-6);
nodeExit.select("text")
.style("fill-opacity", 1e-6);
// Update the links…
var link = vis.selectAll("path.link")
.data(tree.links(nodes), function(d) { return d.target.id; });
// Enter any new links at the parent's previous position.
link.enter().insert("svg:path", "g")
.attr("class", "link")
.attr("d", function(d) {
var o = {x: source.x0, y: source.y0};
return diagonal({source: o, target: o});
})
.transition()
.duration(duration)
.attr("d", diagonal);
// Transition links to their new position.
link.transition()
.duration(duration)
.attr("d", diagonal);
// Transition exiting nodes to the parent's new position.
link.exit().transition()
.duration(duration)
.attr("d", function(d) {
var o = {x: source.x, y: source.y};
return diagonal({source: o, target: o});
})
.remove();
// Stash the old positions for transition.
nodes.forEach(function(d) {
d.x0 = d.x;
d.y0 = d.y;
});
}
// Toggle children.
function toggle(d) {
// I could retrieve the child nodes here, but how to add them to the tree?
if (d.children) {
d._children = d.children;
d.children = null;
} else {
d.children = d._children;
d._children = null;
}
}
答案 0 :(得分:24)
我可以通过在切换功能中添加以下代码来动态添加节点:
$.getJSON(addthese.json, function(addTheseJSON) {
var newnodes = tree.nodes(addTheseJSON.children).reverse();
d.children = newnodes[0];
update(d);
});
注意:我使用jQuery来检索json文件
答案 1 :(得分:0)
我是D3的新手,但这个原始代码可能会有所帮助。您可以创建一个JSON对象并将其推送到树/链接中。然后,这只是重绘树的问题。
function createTreeNode(source){
var current_node = tree.nodes(source);
var myJSONObject = {"name": "new Node","children": []};
if(current_node[0]._children!=null){
current_node[0]._children.push(myJSONObject);
console.log(current_node[0]._children);
source.children = source._children;
source._children = null;
}
else if(current_node[0].children!=null && current_node[0]._children!=null){
current_node[0].children.push(myJSONObject);
console.log(current_node[0].children);
}
else{
current_node[0].children=[]
current_node[0].children.push(myJSONObject);
console.log(current_node[0].children);
}
tree.links(current_node).push(current_node[current_node.length-1]);
navigate_tree(source);}