Question

我正试图找出一种从一串文本中获取一系列URL的方法。文本的格式将如下：

这里有一些随机文字

http://techcrunch.com/2012/07/20/kickstarter-flashr-wants-to-make-the-iphones-bezel-a-massive-notification-light/?grcc=88888Z0ZwdgtZ0Z0Z0Z0Z0&grcc2=835637c33f965e6cdd34c87219233711~1342828462249~fca4fa8af1286d8a77f26033fdeed202~510f37324b14c50a5e9121f955fac3fa~1342747216490~0~0~0~0~0~0~0~0~7~3~

http://techcrunch.com/2012/07/20/last-day-to-purchase-extra-early-bird-tickets-for-disrupt-sf/

显然，这些链接可以是任何东西（并且可以有许多链接，这些只是我现在正在测试的链接。如果我使用像我的正则表达式这样的简单URL。

我正在使用：

preg_match_all('((https?|ftp|gopher|telnet|file|notes|ms-help):'.
    '((//)|(\\\\))+[\w\d:#@%/;$()~_?\+-=\\\.&]*)',
    $bodyMessage, $matches, PREG_PATTERN_ORDER);

当我做print_r( $matches);时，得到的结果是：

Array ( [0] => Array (
    [0] => http://techcrunch.com/2012/07/20/kickstarter-flashr-wants-to-make-the-iphon=
    [1] => http://techcrunch.com/2012/07/20/last-day-to-purchase-extra-early-bird-tick= 
    [2] => http://techcrunch.co=
    [3] => http://techcrunch.com/2012/07/20/kickstarter-flashr-wants-to-make-the-ip= 
    [4] => http://techcrunch.com/2012/07/20/last-day-to-purc=
    [5] => http://tec=
)
...

该阵列中的所有项目都不是上述链接的完整链接。

任何人都知道获得我需要的好方法吗？我发现了一堆正则表达式的东西来获取PHP的链接，但它都不起作用。

谢谢！

编辑：

好的，所以我从电子邮件中提取这些链接。该脚本解析电子邮件，抓取邮件正文，然后尝试从中获取链接。调查电子邮件后，似乎是出于某种原因在网址中间添加了一个空格。这是我的PHP脚本看到的正文消息的输出。

 --00248c711bb99ca36d04c54ba5c6 Content-Type: text/plain; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable http://techcrunch.com/2012/07/20/kickstarter-flashr-wants-to-make-the-iphon= es-bezel-a-massive-notification-light/?grcc=3D88888Z0ZwdgtZ0Z0Z0Z0Z0&grcc2= =3D835637c33f965e6cdd34c87219233711~1342828462249~fca4fa8af1286d8a77f26033f= deed202~510f37324b14c50a5e9121f955fac3fa~1342747216490~0~0~0~0~0~0~0~0~7~3~ http://techcrunch.com/2012/07/20/last-day-to-purchase-extra-early-bird-tick= ets-for-disrupt-sf/ --00248c711bb99ca36d04c54ba5c6 Content-Type: text/html; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable

有关如何使其不破坏URL的任何建议？

编辑2

根据Laurnet的建议，我运行了这段代码：

 $bodyMessage = str_replace("= ", "",$bodyMessage);

然而，当我回应它时，它似乎不想替换“=”

 --00248c711bb99ca36d04c54ba5c6 Content-Type: text/plain; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable http://techcrunch.com/2012/07/20/kickstarter-flashr-wants-to-make-the-iphon= es-bezel-a-massive-notification-light/?grcc=3D88888Z0ZwdgtZ0Z0Z0Z0Z0&grcc2= =3D835637c33f965e6cdd34c87219233711~1342828462249~fca4fa8af1286d8a77f26033f= deed202~510f37324b14c50a5e9121f955fac3fa~1342747216490~0~0~0~0~0~0~0~0~7~3~ http://techcrunch.com/2012/07/20/last-day-to-purchase-extra-early-bird-tick= ets-for-disrupt-sf/ --00248c711bb99ca36d04c54ba5c6 Content-Type: text/html; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable

Answer 1

    /**
     *
     * @get URLs from string (string maybe a url)
     *
     * @param string $string

     * @return array
     *
     */
    function getUrls($string) {
        $regex = '/https?\:\/\/[^\" ]+/i';
        preg_match_all($regex, $string, $matches);
        //return (array_reverse($matches[0]));
        return ($matches[0]);
}

Answer 2

请改用以下正则表达式。

$regex = "(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))";

希望它有所帮助。

使用php获取字符串中的所有URL

2 个答案: