Question

假设我有以下字符串：

"present present present presenting presentation do  do doing "

我按照频率按降序排列字符串中的单词：

I'm using GroupBy count 
present    3
do         2
doing      1
presenting 1
presentation 1

然后，我正在说出这些话：

using array [ , ] or any other structure

present  3
do       2
do       1
present  1
present  1

最后，我想将这些单词重新计入字典。所以输出应该是：

present 5
do      3

任何人都可以帮忙吗？提前致谢。

Answer 1

//使用List而不是Dictionary来允许键多重性：列表＆gt; words = new List＆lt; KeyValuePair＆GT;（）;

        string text = "present present present presenting presentation do  do doing";
        var ws = text.Split(' ');

        //Passing the words into the list:
        words = (from w in ws
                 group w by w into wsGroups
                 select new KeyValuePair<string, int>(
                     wsGroups.Key, ws.Count()
                     )
                 ).ToList<KeyValuePair<string, int>>();

        //Ordering:
        words.OrderBy(w => w.Value);

        //Stemming the words:
        words = (from w in words
                 select new KeyValuePair<string, int>
                     (
                         stemword(w.Key),
                         w.Value
                     )).ToList<KeyValuePair<string, int>>();

        //Sorting and put into Dictionary:
        var wordsRef = (from w in words
                        group w by w.Key into groups
                        select new
                        {
                            count = groups.Count(),
                            word = groups.Key
                        }).ToDictionary(w => w.word, w => w.count);

Answer 2

LINQ GroupBy或Aggregate是计算此类计数的好方法。

如果你想手工做...看起来你想要有两组结果：一个非词干，另一个词干：

void incrementCount(Dictionary<string, int> counts, string word)
{
  if (counts.Contains(word))
  {
    counts[word]++;
  }
  else
  {
    counts.Add(word, 0);
  }
}

var stemmedCount = new Dictionary<string, int>();
var nonStemmedCount = new Dictionary<string, int>();

foreach(word in words)
{
  incrementCount(stemmedCount, Stem(word));
  incrementCount(nonStemmedCount, word);
}

在词干之后计算词频

2 个答案: