Question

不得不说我大约两周前就开始学习Clojure了，现在我整整三天都遇到了问题。

我有一张这样的地图：

{
  :agent1 {:name "Doe" :firstname "John" :state "a" :time "VZ" :team "X"}
  :agent2 {:name "Don" :firstname "Silver" :state "a" :time "VZ" :team "X"}
  :agent3 {:name "Kim" :firstname "Test" :state "B" :time "ZZ" :team "G"}
}

并需要将:team "X"更改为:team "H"。我试过很多像assoc，update-in等等的东西，但没有任何作用。

我怎么做我的东西？非常感谢你！

Answer 1

assoc-in用于替换或插入path

指定的映射中的值

(def m { :agent1 {:name "Doe" :firstname "John" :state "a" :time "VZ" :team "X"}
         :agent2 {:name "Don" :firstname "Silver" :state "a" :time "VZ" :team "X"}
         :agent3 {:name "Kim" :firstname "Test" :state "B" :time "ZZ" :team "G"}})

(assoc-in m [:agent1 :team] "H")

{:agent1 {:state "a", :team "H", :name "Doe", :firstname "John", :time "VZ"},
 :agent2 {:state "a", :team "X", :name "Don", :firstname "Silver", :time "VZ"},
 :agent3 {:state "B", :team "G", :name "Kim", :firstname "Test", :time "ZZ"}}

但是，如果您想要更新所有团队＆＃34; X＆＃34;，无论特定路径如何，在树的所有递归级别上，您都可以使用clojure.walk的预走或后步行功能与您自己的功能相结合：

(use 'clojure.walk)
(defn postwalk-mapentry
    [smap nmap form]
(postwalk (fn [x] (if (= smap x) nmap x)) form))

(postwalk-mapentry [:team "X"] [:team "T"] m)

{:agent1 {:state "a", :team "T", :name "Doe", :firstname "John", :time "VZ"},
 :agent2 {:state "a", :team "T", :name "Don", :firstname "Silver", :time "VZ"},
 :agent3 {:state "B", :team "G", :name "Kim", :firstname "Test", :time "ZZ"}}

Answer 2

步行功能很适合那样更换。

(clojure.walk/prewalk-replace {[:team "X"] [:team "H"]} map)

传入向量可以确保您不仅仅替换所有“X”。

Clojure嵌套地图 - 更改值

2 个答案: