Question

我正在使用自定义mixin将过滤器应用于使用MultipleObjectMixin分页的基于类的视图的查询集。当我应用过滤器使得当前页面在数据集范围之外时，我显然得到404.我想要做的是捕获此异常并将其重定向到新的最后一页。

我对相关视图的get_queryset：

def get_queryset(self):
    filters = self.build_location_filter()
    if not filters == None:
        return models.Account.corporateAccounts(locations=self.build_location_filter)
    else:
        return models.Account.corporateAccounts()

有什么建议吗？

Answer 1

尝试：

def get(self, request, *args, **kwargs):
    try:
        return super(MyView, self).get(request, *args, **kwargs)
    except Http404:
        if kwargs['page'] > self.paginator.num_pages:
            return HttpResponseRedirect(reverse('this_view_paged', kwargs={'page': self.paginator.num_pages}))
        else:
            # re-raise Http404, as the reason for the 404 was not that maximum pages was exceeded
            raise Http404(_(u"Empty list and '%(class_name)s.allow_empty' is False.")
                      % {'class_name': self.__class__.__name__})

<强>更新

对不起。我真的认为Django将paginator添加为实例变量。真的糟透了它没有，因为它使它比它需要的难度高100倍。分页器在paginate_queryset中被捕获，这实际上是Http404被提升的地方。这意味着，您甚至无法调用此方法来获取您的分页器，因为您从中获得的所有内容都是例外。所以，你必须更深入，不幸的是重复一些Django视图逻辑，我讨厌做，但这是我能看到的唯一前进道路。由于我们正在使用代码重复，无论如何，我现在正在覆盖整个paginate_queryset方法。新的代码直接从Django源代码中复制，并在注释部分中进行了修改（我已将上面的原始代码完整保留给后代）：

def paginate_queryset(self, queryset, page_size):
        """
        Paginate the queryset, if needed.
        """
        paginator = self.get_paginator(queryset, page_size, allow_empty_first_page=self.get_allow_empty())
        page = self.kwargs.get('page') or self.request.GET.get('page') or 1
        try:
            page_number = int(page)
        except ValueError:
            if page == 'last':
                page_number = paginator.num_pages
            else:
                raise Http404(_(u"Page is not 'last', nor can it be converted to an int."))
        try:
            page = paginator.page(page_number)
            # Moving this line after the try/except block because DRY
            #return (paginator, page, page.object_list, page.has_other_pages())
        except InvalidPage:
            # This used to raise a 404, but we're replacing this functionality
            #raise Http404(_(u'Invalid page (%(page_number)s)') % {
            #                    'page_number': page_number
            #})
            page = paginator.page(paginator.num_pages)

        return (paginator, page, page.object_list, page.has_other_pages())

在get_queryset中过滤时重置MultipleObjectMixin分页

1 个答案: