Question

所以我正在创建一个程序，它有一个大约需要20个变量的类（让我们称之为Person类）。当我尝试像这样初始化变量时：

Person Steph = new Person(SName, SAge, SPhysical, SJob, SEducation, SPastSecret, SSecret1, Secret2, SSecret3, SConnections, SLikes, SHates, SCondtion, SNAME, SAGE, SPHYSICAL, SJOB, SEDUCATION, SPASTSECRET, SSECRET1, SECRET2, SSECRET3, SCONNECTIONS);

我收到错误：

internal error; cannot instantiate Person.<init> at Person to

然后列出变量。有人知道是什么导致了这个错误吗？

编辑：这是Person的完整代码：

class Person extends Detect{
public String Name, Age, Physical, Job, Education, PastSecret, Secret1, Secret2, Secret3, Connections, Likes, Hates, Condition;
public boolean NAME, AGE, PHYSICAL, JOB, EDUCATION, PASTSECRET, SECRET1, SECRET2, SECRET3, CONNETCTIONS, LIKES, HATES, CONDITION;

public Person(String Name, String Age, String Physical, String Job, String Education, 
String PastSecret, String Secret1, String Secret2, String Secret3, String Connections, String Likes, 
String Hates, String Condition, boolean NAME, boolean AGE, boolean PHYSICAL, boolean JOB, boolean EDUCATION,
boolean PASTSECRET, boolean SECRET1, boolean SECRET2, boolean SECRET3, boolean CONNECTIONS, 
boolean LIKES, boolean HATES, boolean CONDITION) {

    this.Name = Name;
    this.Age = Age;
    this.Physical = Physical;
    this.Job = Job;
    this.Education = Education;
    this.PastSecret = PastSecret;
    this.Secret1 = Secret1;
    this.Secret2 = Secret2;
    this.Secret3 = Secret3;     
    this.Connections = Connections;
    this.Likes = Likes;
    this.Hates = Hates;
    this.Condition = Condition;
    this.NAME = NAME;
    this.AGE = AGE;
    this.PHYSICAL = PHYSICAL;
    this.JOB = JOB;
    this.EDUCATION = EDUCATION;
    this.PASTSECRET = PASTSECRET;
    this.SECRET1 = SECRET1;
    this.SECRET2 = SECRET2;
    this.SECRET3 = SECRET3;
    this.CONNECTIONS = CONNECTIONS;
    this.LIKES = LIKES;
    this.HATES = HATES;
    this.CONDITION = CONDITION;

}



public void File(){
    System.out.printf("Suspect Name: %s         Age: %s       Appearance: %s\n", Check(NAME, Name), Check(AGE, Age),
        Check(PHYSICAL, Physical));
    System.out.printf("Job: %s          Education: %s           Past Secret: %s\n", Check(JOB, Job), Check(EDUCATION, Education), 
        Check(PASTSECRET, PastSecret));
    System.out.printf("Connections: %s    Secret: %s      Secret: %s    Secret: %s\n", Check(CONNECTIONS, Connections), Check(SECRET1, Secret1),
        Check(SECRET2, Secret2), Check(SECRET3, Secret3));
    System.out.printf("Likes: %s    Hates: %s    Conditions: %s\n\n", Check(LIKES, Likes), Check(HATES, Hates), Check(CONDITIONS, Conditions));
}

}

Answer 1

您将23个参数传递给具有26个参数的构造函数。

Answer 2

首先，不要让类构造函数传递20个变量。创建一个POJO对象并使用它。例如：

public class Structure {
   private Object someObj;

   private Object someObj2;

   private Object someObj3;

   private Object someObj4;

   //getters and setters
}

在将其发送到Person类构造函数之前，通过setter方法设置所需的变量，并仅传递此Structure类。（这使您的代码更有效，更易读，适用于全球社区和您自己。）

关于初始化。你确定Person class'构造函数接受所有20个变量吗？我很确定你的Person类构造函数是错误的。试试这种方式，这应该有效。

Answer 3

Person.<init>指的是Person类的构造函数。

错误表明Person类的构造函数与您提供的参数不匹配。不幸的是，它没有告诉你原因。

您可能希望下载并安装集成开发环境（IDE），例如Eclipse。它将为您提供有关此类编程问题的更多信息，并使编码变得更加容易。

内部错误;无法实例化<class>。<init> </init> </class>

3 个答案: