Question

我正试图找到一种方法来输入电话号码的字段限制。例： France (country code 33) local number 0142687984应输入为 33142687984

而不是例如 00331 42687984, 0033 (1) 42687984, +33 1 42 68 79 84等

基本上数字永远不应该以0开头，不应该包含+（）等空格或符号，并且应该至少有9位

我一直在尝试为洪流脚本找到一个示例，但没有成功。请帮忙

到目前为止，我有这个：

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    // TODO Auto-generated method stub

    String nom = request.getParameter("nom");
    String prenom = request.getParameter("prenom");
    String phone = request.getParameter("phone");
    String adressefacturation = request.getParameter("adressefacturation");
    String ZIPfacturation = request.getParameter("ZIPfacturation");
    String paysfacturation = request.getParameter("paysfacturation");
    String adresseexpedition = request.getParameter("adresseexpedition");
    String ZIPexpedition = request.getParameter("ZIPexpedition");

    String paysexpedition = request.getParameter("paysexpedition");
    String CardNumber = request.getParameter("CardNumber");
    String CardDateOfExpiry = request.getParameter("CardDateOfExpiry");

    String password = request.getParameter("password");         
}

Answer 1

“基本上数字永远不应该从0开始，不应该包含空格或符号，如+（）等，并且应该至少有9位”所以我假设你只接受以1-9位开头的数字然后只能包含其他数字（至少8个）。

这就是你想要的东西试试这个正则表达式[1-9][0-9]{8,}

System.out.println("123456789".matches("[1-9][0-9]{8,}"));//true
System.out.println("12345678".matches("[1-9][0-9]{8,}"));//false
System.out.println("012345678".matches("[1-9][0-9]{8,}"));//false

Answer 2

使用正则表达式匹配/^33\d{9}$/

Answer 3

要计算一些可能性，你必须拆分输入的字符串（在测试“..（1）..”之后）：

    // String[] litteralPhone = request.getParameter("phone").split(" ") ;
    final String litteralPhone = "0033 (119999999990";
    final int i = litteralPhone.indexOf(")");
    if (i > 0) {
        if (litteralPhone.substring(i).length() > 8) {
            System.out.println(litteralPhone.replaceAll(
                "^[0]{1,}|[ ]{0,}\\(|\\)[ ]{0,}", ""));
        } else {
            System.out.println("error with ()");
        }
    } else {
        // suppress trailing ( 
        final String[] tabNum = litteralPhone.replaceAll("\\(|\\)", "").split(" ");

        switch (tabNum.length) {
            case 1 : // 003311236549879879
               tabNum[0] = tabNum[0].replaceAll("^[0]{1,}", "");
               if (tabNum[0].length() < 10) { // tune this lenght
                      System.out.println("error 1");
                }
                break;
            case 2 : // 033 01234567890
                tabNum[0] = tabNum[0].replaceAll("^[0]{1,}", "");
                tabNum[1] = tabNum[1].replaceAll("^[0]", "");
                if (tabNum[1].length() < 8) {
                    System.out.println("error 2");
                }
                break;
            case 3 : // +33 1 012346577979
                tabNum[0] = tabNum[0].replaceAll("^[0]{1,}", "");
                tabNum[2] = tabNum[2].replaceAll("^[0]", "");
                if (tabNum[2].length() < 8) {
                    System.out.println("error 3");
                }
                // add all cases here
            default :
                System.out.println("not a good phone number");
                break;
        }
        final StringBuilder sb = new StringBuilder();
        for (final String string : tabNum) {
            sb.append(string);
        }
        System.out.println(sb.toString());
    }

输入验证电话号码

3 个答案: