Question

我开始关注elasticsearch，我想知道这个操作是否可以用它完成:(我做了一些搜索，但我承认我不知道该寻找什么）。

我有这两个联系人数据：

{
  "id"     : "id1",
  "name"   : "Roger",
  "phone1" : "123",
  "phone2" : "",
  "phone3" : "980"
}

{
  "id"     : "id2",
  "name"   : "Lucas",
  "phone1" : "789",
  "phone2" : "123",
  "phone3" : ""
}

我很想知道elasticsearch是否可以帮助我找到重复的电话号码，即使它们位于不同的电话领域（这两个记录中都有“123”）。我已经看到我可以在多个字段中搜索字符串，所以如果我搜索123，我可以得到这两个记录。但是，我希望有能力发出一个请求，可以返回我这样的内容：

{
  "phones" : {
    "123" : ["id1", "id2"],
    "980" : ["id1"],
    "789" : ["id2"]
  }
}

或者即使这样也很有用（带号码的联系人数量）：

{
  "phones" : {
    "123" : 2,
    "980" : 1,
    "789" : 1
  }
}

知道这是否可行？如果可以的话，这将是非常棒的。

Answer 1

我同意DrTech的建议，即改变您的数据结构。但是，如果您出于某种原因希望保持原样，您可以使用多字段术语方面获得相同的结果：

curl "localhost:9200/phonefacet/_search?pretty=true&search_type=count" -d '{
    "query" : {
        "match_all" : {  }
    },
    "facets" : {
        "tag" : {
            "terms" : {
                "fields" : ["phone1", "phone2", "phone3"],
                "size" : 10
            }
        }
    }
}'

结果如下：

{
  "took" : 1,
  "timed_out" : false,
  "_shards" : {
    "total" : 5,
    "successful" : 5,
    "failed" : 0
  },
  "hits" : {
    "total" : 2,
    "max_score" : 0.0,
    "hits" : [ ]
  },
  "facets" : {
    "tag" : {
      "_type" : "terms",
      "missing" : 2,
      "total" : 4,
      "other" : 0,
      "terms" : [ {
        "term" : "123",
        "count" : 2
      }, {
        "term" : "980",
        "count" : 1
      }, {
        "term" : "789",
        "count" : 1
      } ]
    }
  }
}

Answer 2

您可以使用terms facet到达那里，但是您必须更改数据结构以将所有电话号码都包含在一个字段中：

创建索引：

curl -XPUT 'http://127.0.0.1:9200/test/?pretty=1'

索引您的数据：

curl -XPOST 'http://127.0.0.1:9200/test/test?pretty=1'  -d '
{
   "name" : "Roger",
   "id" : "id1",
   "phone" : [
      "123",
      "980"
   ]
}
'

curl -XPOST 'http://127.0.0.1:9200/test/test?pretty=1'  -d '
{
   "name" : "Lucas",
   "id" : "id2",
   "phone" : [
      "789",
      "123"
   ]
}
'

搜索所有字段，返回phone中的字词数：

curl -XGET 'http://127.0.0.1:9200/test/test/_search?pretty=1'  -d '
{
   "facets" : {
      "phone" : {
         "terms" : {
            "field" : "phone"
         }
      }
   }
}
'

# {
#    "hits" : {
#       "hits" : [
#          {
#             "_source" : {
#                "name" : "Roger",
#                "id" : "id1",
#                "phone" : [
#                   "123",
#                   "980"
#                ]
#             },
#             "_score" : 1,
#             "_index" : "test",
#             "_id" : "StaJK9A5Tc6AR7zXsEKmGA",
#             "_type" : "test"
#          },
#          {
#             "_source" : {
#                "name" : "Lucas",
#                "id" : "id2",
#                "phone" : [
#                   "789",
#                   "123"
#                ]
#             },
#             "_score" : 1,
#             "_index" : "test",
#             "_id" : "x8w39F-DR9SZOQoHpJw2FQ",
#             "_type" : "test"
#          }
#       ],
#       "max_score" : 1,
#       "total" : 2
#    },
#    "timed_out" : false,
#    "_shards" : {
#       "failed" : 0,
#       "successful" : 5,
#       "total" : 5
#    },
#    "facets" : {
#       "phone" : {
#          "other" : 0,
#          "terms" : [
#             {
#                "count" : 2,
#                "term" : "123"
#             },
#             {
#                "count" : 1,
#                "term" : "980"
#             },
#             {
#                "count" : 1,
#                "term" : "789"
#             }
#          ],
#          "missing" : 0,
#          "_type" : "terms",
#          "total" : 4
#       }
#    },
#    "took" : 5
# }

弹性搜索中的多场操作

2 个答案: