Question

我们正在努力配置我们的Web应用程序，以便能够通过Spring WS连接Web服务。我们尝试使用客户端Spring-WS文档中的示例，但我们最终得到了WebServiceTransportException。 XML配置如下所示：

<bean id="webServiceTemplate" class="org.springframework.ws.client.core.WebServiceTemplate">
    <constructor-arg ref="messageFactory"/>
    <property name="messageSender">
        <bean class="org.springframework.ws.transport.http.CommonsHttpMessageSender">
            <property name="credentials">
                <bean class="org.apache.commons.httpclient.UsernamePasswordCredentials">
                    <constructor-arg value="john"/>
                    <constructor-arg value="secret"/>
                </bean>
            </property>
        </bean>
    </property>
</bean>

我们已经能够以编程方式配置应用程序，但是这种配置无法“转移”到Spring XML配置，因为有些setter没有使用Spring期望的格式。（HttpState.setCredentials（...）有两个参数）。该配置已从该公司的其他一些Spring-WS客户端代码中解除。

这是有效的配置：

 public List<String> getAll() {
    List<String> carTypes = new ArrayList<String>();

    try {
        Source source = new ResourceSource(request);
        JDOMResult result = new JDOMResult();


        SaajSoapMessageFactory soapMessageFactory = new SaajSoapMessageFactory(MessageFactory.newInstance());

        WebServiceTemplate template = new WebServiceTemplate(soapMessageFactory);

        HttpClientParams clientParams = new HttpClientParams();
        clientParams.setSoTimeout(60000);
        clientParams.setConnectionManagerTimeout(60000);
        clientParams.setAuthenticationPreemptive(true);

        HttpClient client = new HttpClient(clientParams);
        client.getState().setCredentials(AuthScope.ANY,
                new UsernamePasswordCredentials("username", "password"));

        CommonsHttpMessageSender messageSender = new CommonsHttpMessageSender(client);

        template.setMessageSender(messageSender);
        template.sendSourceAndReceiveToResult(SERVICE_URI,
                source, result);

        // Handle the XML

    } catch (IOException e) {
        throw new RuntimeException(e);
    } catch (SOAPException e) {
        throw new RuntimeException(e);
    }

    return carTypes;
}

有谁知道如何解决我的问题？我在那里看到的每个教程都列出了第一个配置。看来，当我在messageSender对象上设置凭据时，它们只是被忽略了......

Answer 1

使用构造函数覆盖HttpClient，该构造函数接受参数并使用constructor-args连接Spring

public MyHttpClient(HttpClientParams params, UsernamePasswordCredentials usernamePasswordCredentials) {
        super(params);        
        getState().setCredentials(AuthScope.ANY, usernamePasswordCredentials);
    }

Answer 2

你如何区分这些：

<constructor-arg value="john"/>
<constructor-arg value="secret"/>

尝试将其替换为：

<property name="userName" value="john" />
<property name="password" value="secret" />

希望它有所帮助。

Answer 3

如果您使用的是类似于示例的defaultHttpClient，请在HTTPMessageSender上使用afterPropertiesSet方法，并通过正确应用凭据来解决问题

Answer 4

首先，我们在我们的项目中设置凭据，如下所示：

<bean id="authenticationEnabledCommonsHttpMessageSender" parent="commonsHttpMessageSender"
    p:credentials-ref="clientCredentials" lazy-init="true" />
<bean id="clientCredentials"
    class="org.apache.commons.httpclient.UsernamePasswordCredentials"
    c:userName="${clientCredentials.userName}"
    c:password="${clientCredentials.password}"
    lazy-init="true" />

这是我们启用cridentials的选项。我们设置这样的凭据时出现问题。如果我们发送消息的服务器（有Axis impl）没有用户名密码凭据，我们会收到“未经授权”的异常。因为，当我们跟踪TCPMon时，我们发现了“username：password：”字符串已发送，因为您可以看到用户名和密码没有任何价值。

之后我们设置如下凭据：

public Message sendRequest(OutgoingRequest message, MessageHeaders headers,
                        EndpointInfoProvider endpointInfoProvider,
                        WebServiceMessageCallback requestCallback){
    Assert.notNull(endpointInfoProvider, "Destination provider is required!");
    final Credentials credentials = endpointInfoProvider.getCredentials();
    URI destinationUri = endpointInfoProvider.getDestination();
    for (WebServiceMessageSender messageSender : webServiceTemplate.getMessageSenders()) {
        if (messageSender instanceof CommonsHttpMessageSender) {
            HttpClient httpClient = ((CommonsHttpMessageSender) messageSender).getHttpClient();
            httpClient.getState().setCredentials(
                    new AuthScope(destinationUri.getHost(),
                            destinationUri.getPort(), AuthScope.ANY_REALM,
                            AuthScope.ANY_SCHEME), credentials
            );
            httpClient.getParams().setAuthenticationPreemptive(true);
            ((CommonsHttpMessageSender) messageSender)
                    .setConnectionTimeout(endpointInfoProvider
                            .getTimeOutDuration());
        }
    }

getCredentials方法是：

@Override
public Credentials getCredentials(){
    if (credentials != null) {
        return credentials;
    }
    String username = parameterService.usernameFor(getServiceName());
    String password = parameterService.passwordFor(getServiceName());
    if (username == null && password == null) {
        return null;
    }
    credentials = new UsernamePasswordCredentials(username, password);
    return credentials;
}

WebServiceTransportException：Spring-WS中未授权[401]

4 个答案: