Question

我有一个看起来像这样的html表单：

<div class="field>
  <input id="product_name" name="product[name]" size="30" type="text"/>
</div>

<div class="field>
  <input id="product_picture" name="product[picture]" size="30" type="file"/>
</div>

我想编写一个自动创建产品的Java模块。这是我已经拥有的：

HttpHost host = new HttpHost("localhost", 3000, "http");
HttpPost httpPost = new HttpPost("/products");
List<BasicNameValuePair> data = new ArrayList<BasicNameValuePair>();
data.add(new BasicNameValuePair("product[name]", "Product1"));
UrlEncodedFormEntity entity = new UrlEncodedFormEntity(data, "UTF-8");
httpPost.setEntity(entity);
HttpResponse postResponse = httpClient.execute(host, httpPost);

这很好用，它可以创建名为“Product1”的新产品。但我不知道如何处理上传部分。我希望看起来像这样：

data.add(new BasicNameValuePair("product[name]", "Product1"));

但不是“Product1”，而是文件。我阅读了HttpClient的文档，据说只有字符串。

有谁知道如何处理上传部分？

Answer 1

依赖关系：

<dependency>
 <groupid>org.apache.httpcomponents</groupid>
 <artifactid>httpclient</artifactid>
 <version>4.0.1</version>
</dependency>

<dependency>
 <groupid>org.apache.httpcomponents</groupid>
 <artifactid>httpmime</artifactid>
 <version>4.0.1</version>
</dependency>

代码：[棘手的部分是使用MultipartEntity]

HttpClient client = new DefaultHttpClient();
client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION,HttpVersion.HTTP_1_1);
HttpPost post = new HttpPost( url );
MultipartEntity entity = new MultipartEntity( HttpMultipartMode.BROWSER_COMPATIBLE );
// For File parameters
entity.addPart( paramName, new FileBody((( File ) paramValue ), "application/zip" ));
// For usual String parameters
entity.addPart( paramName, new StringBody( paramValue.toString(), "text/plain", Charset.forName( "UTF-8" )));
post.setEntity( entity );
// Here we go!
String response = EntityUtils.toString( client.execute( post ).getEntity(), "UTF-8" );
client.getConnectionManager().shutdown();

Answer 2

使用HTTP请求的另一种更快捷方式是使用curl。

使用HttpClient POST提交带有上传的表单

2 个答案: