模型定义:
class Article < ActiveRecord::Base
has_and_belongs_to_many :groups
end
class Group < ActiveRecord::Base
has_and_belongs_to_many :articles
has_many :domains, :inverse_of=>:group
end
class Domain < ActiveRecord::Base
belongs_to :group, :inverse_of=>:domains
has_many :pages, :inverse_of=>:domain
end
class Page < ActiveRecord::Base
belongs_to :domain, :inverse_of=>:pages
belongs_to :article, :inverse_of=>:pages
end
对于特定的Article
,我想选择所有Domains
(通过groups.domains
关联),而Page
与Article
没有关联。
class Article < ActiveRecord::Base
has_and_belongs_to_many :groups
def avaiable_domains
groups.domains("where not exists page with article_id=#{id}")) ##????
#I have code mentioned at the end of this question, but I don't want use SQL, just pure active query
end
end
是否可以在纯Active Record Query或Arel中编写它(在where where方法中没有SQL)?
现在我正在使用它:
Domain.where(:group_id=>group_ids).where('NOT EXISTS(SELECT 1 FROM pages WHERE pages.domain_id=domains.id AND article_id=?)',id)
答案 0 :(得分:0)
Domain.joins(:groups => :articles, :pages).where("pages.article_id <> :id AND articles.id = :id", id: article_id)
域模型中的
scope :available, ->(article_id){ joins(:groups => :articles,:pages).
where("pages.article_id <> :id AND articles.id = :id", id: article_id)
文章模型中的
def available_domains
Domain.available(id)
end