您好我已经在我的Android应用程序中通过soap webservices使用MySQL连接开发了一个登录表单(用户名,密码和提交按钮)。 在这里我忘了我的密码意味着我无法访问我的帐户。然后如何访问我的帐户。首先注册页面在登录之前完成所有登录页面。注册页面有用户名,密码和电子邮件。所以当我忘记密码意味着点击忘记密码textview.then它是去忘记密码活动。当我输入我的注册电子邮件ID意味着我的密码发送到我的电子邮件id.how我可以做。请指导我。 如下图所示:
如何在activity的XML资源中创建dis app.I done dis code。我是否创建了ForgetPassword Java代码?我似乎无法做到这一点。
仍然是我的java代码:
Login.java:
package com.soap;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.PropertyInfo;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
public class Login extends Activity {
private final String NAMESPACE = "http://ws.userlogin.com";
private final String URL = "http://192.168.1.168:8085/Login/services/Login?wsdl";
private final String SOAP_ACTION = "http://ws.userlogin.com/authentication";
private final String METHOD_NAME = "authentication";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.login);
Button register = (Button) findViewById(R.id.btn_reg);
register.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
// Switching to Register screen
Intent i = new Intent(getApplicationContext(), Register.class);
startActivity(i);
}
});
Button logout = (Button) findViewById(R.id.btn_logout);
logout.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
// Switching to Register screen
Intent i = new Intent(getApplicationContext(), Login.class);
startActivity(i);
}
});
TextView forgetpassword = (TextView) findViewById(R.id.TextView03);
forgetpassword.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
// Switching to Register screen
Intent i = new Intent(getApplicationContext(), ForgetPassword.class);
startActivity(i);
}
});
Button login = (Button) findViewById(R.id.btn_login);
login.setOnClickListener(new View.OnClickListener() {
public void onClick(View arg0) {
loginAction();
}
});
}
private void loginAction(){
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
EditText userName = (EditText) findViewById(R.id.tf_userName);
String user_Name = userName.getText().toString();
EditText userPassword = (EditText) findViewById(R.id.tf_password);
String user_Password = userPassword.getText().toString();
//Pass value for userName variable of the web service
PropertyInfo unameProp =new PropertyInfo();
unameProp.setName("userName");//Define the variable name in the web service method
unameProp.setValue(user_Name);//set value for userName variable
unameProp.setType(String.class);//Define the type of the variable
request.addProperty(unameProp);//Pass properties to the variable
//Pass value for Password variable of the web service
PropertyInfo passwordProp =new PropertyInfo();
passwordProp.setName("password");
passwordProp.setValue(user_Password);
passwordProp.setType(String.class);
request.addProperty(passwordProp);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
try{
androidHttpTransport.call(SOAP_ACTION, envelope);
SoapPrimitive response = (SoapPrimitive)envelope.getResponse();
String status = response.toString();
TextView result = (TextView) findViewById(R.id.tv_status);
result.setText(response.toString());
if(status.equals("Success!"))
{
Intent intent = new Intent(Login.this,HomePage.class);
intent.putExtra("username",userName.getText().toString());
startActivity(intent);
}
else
{
Intent i = new Intent(getApplicationContext(), Login.class);
startActivity(i);
}
}
catch(Exception e){
}
}
}
答案 0 :(得分:2)
如果用户密码未加密。
1 - 创建一个webservice emailPasswordToUser 这个“emailPasswordToUser”网络服务将收到一个“emailaddress”参数,用户将在您的Android应用程序中输入该参数,在提交按钮后,您的“emailPasswordToUser”将通过KSOAP库点击。
“emailPasswordToUser”此网络服务将检查:
A - 用户电子邮件地址是否确实存在于数据库中。
B - 如果存在,它将从Web服务参数收到的“emailaddress”中检索用户信息,并将用户密码通过电子邮件发送到此“emailaddress”,并将消息返回到Android端,将被解析为“您的密码已发送到您的电子邮件地址“
C - 如果它不存在,webservice将返回消息“不存在此类用户”
由于
答案 1 :(得分:0)
您必须创建一些服务器,可以访问MySQL,通过电子邮件找到密码并向用户发送电子邮件。你不应该在应用程序中这样做。
答案 2 :(得分:0)