Question

我想从外部文本中删除所有php标记，以便它可以安全地包含在php中。

这是示例输入：

<?
?>
<html>
<?php ?>
<?= ?>
</html>
<?

或任何其他可能性

并输出：

<html>
</html>

最后一个php open标签可能没有结束标签！

Answer 1

我认为没有一种很好的方法可以完全按照您的要求进行操作，但如果在输出中发送PHP标记（未解析）是可以接受的，那么您可以使用：

<?php echo file_get_contents('input.html'); ?>

否则，请查看token_get_all方法：

http://www.php.net/manual/en/function.token-get-all.php

您可以迭代所有结果，只返回T_INLINE_HTML类型的结果：

$toks = token_get_all( file_get_contents( 'input.html' ) );
foreach( $toks as $tok ) {
  if( $tok[0] == T_INLINE_HTML )   {
    print $tok[1];
  }
}

Answer 2

执行此操作的正确方法是不包含它，而是使用file_get_contents()将其作为字符串加载。这将保留PHP标记而不执行它们。但是，以下正则表达式将完全按照您的要求执行：

#<\?.*?(\?>|$)#s

以下是该字符串代表的细分：

#       A delimiter marking the beginning and end of the expression - nearly anything will do (preferably something not in the regex itself)
<\?      Find the text "<?", which is the beginning of a PHP tag.  Note that a backslash before the question mark is needed because question marks normally do something special in regular expressions.
.*?     Include as much text as necessary (".*"), but as little as possible ("?").
(\?>|$)  Stop at an ending PHP tag ("?>"), OR the end of the text ("$").  This doesn't necessarily have to stop at the first one, but since the previous part is "as little as possible", it will.
#       The same delimiter, marking the end of the expression
s       A special flag, indicating that the pattern can span multiple lines.  Without it, the regex would expect to find the entire PHP tag (beginning and end) on a single line.

剥离PHP标签preg_replace

2 个答案: