Question

我如何创建一个随机图像生成器，它不会重复图像，直到它们通过它们一次？

例如：

- （IBAction）randomimagebutton {

int randomimages = rand() % 5;

switch (randomimages) {

    case 0:
        imageview.image = [UIImage imageNamed:@"IMAGE_001.png"];
        break;
    case 1:
        imageview.image = [UIImage imageNamed:@"IMAGE_002.png"];
        break;
    case 2:
        imageview.image = [UIImage imageNamed:@"IMAGE_003.png"];
        break;
    case 3:
        imageview.image = [UIImage imageNamed:@"IMAGE_004.png"];
        break;
    case 4:
        imageview.image = [UIImage imageNamed:@"IMAGE_005.png"];
        break;

default:

        break;

}

如果图像按顺序出现：1,4,2,5,4,3我怎样才能确保在显示所有5张图像之前不再出现“4”？

感谢您的帮助！

Answer 1

将图像名称存储在NSMutableArray中并随机播放阵列，例如通过类似的方法 this SO answer

然后遍历数组。

Answer 2

创建一个NSMutableArray并在其上放置0,1,2,3,4然后每当选择一个随机数时将其删除如下：

[myNSMutableArray removeObjectAtIndex:myRandNumber];


To fill the gap, all elements beyond index are moved by subtracting 1 from their index.

然后只需选择一个新的随机：

int randomimages = rand() % 4; //4 would of course be a int var that you substract everytime a new random is generated.

等等。

随机图像生成器，不重复xcode

2 个答案: