可能重复:
put the value of radio button and check box into database PHP
我在menu2.php上收到错误消息“Undefined Index”,这是
$Field = mysql_real_escape_string($_POST['field3']);
resto.php
Menu :
<input type="checkbox" value="Siomay" name="tile[]">Siomay <br>
<input type="radio" name="field1[]" value="4" />Small
<input type="radio" name="field1[]" value="5" />Large<br>
<input type="checkbox" value="Batagor" name="tile[]">Batagor <br>
<input type="radio" name="field2[]" value="4" />Small
<input type="radio" name="field2[]" value="5" />Large<br>
<input type="checkbox" value="Pempek" name="tile[]">Pempek<br>
<input type="radio" name="field3[]" value="4" />Small
<input type="radio" name="field3[]" value="5" />Large<br>
<input name="confirm" type=submit id="confirm" value='Confirm'>
</form>
menu2.php
<?php
$con = mysql_connect("localhost","root");
if (!$con) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db("project1", $con);
$Tile = mysql_real_escape_string($_POST['tile']);
$Field = mysql_real_escape_string($_POST['field1']);
$Field = mysql_real_escape_string($_POST['field2']);
$Field = mysql_real_escape_string($_POST['field3']);
if ( !empty($Tile) && !empty($Field) ) {
$insert="INSERT INTO menu(name, price) VALUES ('$Tile','$Field')";
if (!mysql_query($insert, $con)) {
die('Error: ' . mysql_error());
}
echo "1 record added";
}
else echo "Please select at least 1 menu.";
mysql_close($con)
?>