Question

请考虑这种情况：

我有一张这样的表：

ID              City            Status
--------------------------------------
 1               1                1
 2               1                1
 3               1                1
 4               2                1
 5               2                0
 6               3                1
 7               3                1
 8               3                1
 9               3                1
 10              4                3
 11              4                1
 12              4                0

我想返回Citis所有与该城市相关的记录都有Status=1，并且其中一条记录中有Status<>1该城市从reslut集中排除。在这种情况下，我想回归城市：1,3。

如何使用Sql Query或LINQ查询执行此操作？

感谢

Answer 1

这样的事情应该这样做。

LINQ：

var citiesToExclude = context.Table
    .Where(t => t.Status != 1)
    .Select(t => t.City);
var cities = context.Table
    .Where(t => t.Status == 1)
    .Where(t => !citiesToExclude.Contains(t.City))
    .Select(t => t.City)
    .Distinct()
    .ToList();

SQL：

SELECT City
FROM [Table]
WHERE Status == 1
  AND City NOT IN (SELECT City FROM [Table] WHERE Status <> 1)
GROUP BY City

希望这有帮助。

Answer 2

您可以简单地将GROUP BY和HAVING与条件聚合一起使用：

SELECT   city
FROM     tbl
GROUP BY city
HAVING   COUNT(CASE WHEN status <> 1 THEN 1 END) = 0

Answer 3

另一种方式

select distinct city 
from city C1
 where city=1 and not exists(select * from city C2 where C1.city=C2.city 
 and isnull(Status,0)<>1)

Answer 4

SELECT tbl.city
FROM 
(SELECT c.city, count(status=1) cnt1, count() cnt2
FROM city c
GROUP BY c.city) AS tbl
WHERE tbl.cnt1=tbl.cnt2 AND tbl.cnt1>0

Answer 5

为什么你不能用它？该函数似乎没有聚合，因此不需要having

select city 
from [table]
where status = 1
and city not in 
(select city from table where status <> 1)
group by city;

除非我误解了这个问题？

Answer 6

这看起来像LINQ的group子句的工作：

var cities = from t in table
             group t by t.City into grp
             where grp.Select(g => g.Status).All(s => s == 1)
             select g.Key;

返回与该项目相关的所有记录都具有特定条件的项目

6 个答案: