我有这个问题:
(from a in SickDays
join b in Class.Where(p => p.ID == myId) on a.Class_ID equals b.ID
join c in Student on a.Student_ID equals c.ID
group a by new { c.Name, c.Order } into ac
select new { Count = ac.Count(), Name = ac.Key.Name, Order = ac.Key.Order }
).OrderBy(f => f.Order)
返回:
Count | Name | Order
3 | Dave | a
2 | John | b
7 | Sally| c
但是我希望它能归还:
Count | Name | Order
3 | Dave | a
2 | John | b
7 | Sally| c
0 | Mark | d
0 | Betty| e
更新 这就是使用@sixlettervariables示例学生,课程和病假的样子:
var Students = new List<Student>()
{
new Student { Id = 1, Name = "Al", Order = 'a' },
new Student { Id = 2, Name = "Betty", Order = 'b' },
new Student { Id = 3, Name = "Charles", Order = 'c' },
};
var Classes = new List<Class>()
{
new Class { Id = 1, Title = "A100" },
new Class { Id = 2, Title = "A200" },
};
var SickDays = new List<SickDay>()
{
new SickDay { Id = 1, StudentId = 1, ClassId = 1 },
new SickDay { Id = 2, StudentId = 1, ClassId = 1 },
new SickDay { Id = 3, StudentId = 1, ClassId = 2 },
new SickDay { Id = 4, StudentId = 1, ClassId = 2 },
new SickDay { Id = 5, StudentId = 2, ClassId = 1 },
};
好的以上现在是正确的,很抱歉这个混乱!
答案 0 :(得分:4)
这被称为Left Outer Join。在这种情况下,即使没有 Sick Days ,每个 Student 也是必需的。因此,我们将从学生开始,在病假时执行左外连接,然后返回与您指定的ID匹配的类的计数:
var query =
from s in Students
join d in SickDays on s.ID equals d.Student_ID into gj
from sd in gj.DefaultIfEmpty()
group sd by new { s.Name, s.Order } into gg
select
new
{
Name = gg.Key.Name,
Order = gg.Key.Order,
Count = gg.Count(x => x != null && x.Class_ID == myId)
};
答案 1 :(得分:0)
所以即使他们不在课堂上,你也想要所有的学生?然后你需要一个我认为的左连接。使用Linq,这是使用DefaultIfEmpty()
实现的试试这个?
(from a in SickDays
join b in Class.Where(p => p.ID == myId) on a.Class_ID equals b.ID
join c in Student on a.Student_ID equals c.ID
into s
from students in s.DefaultIfEmpty()
group a by new { students.Name, students.Order } into ac
select new { Count = ac.Count(), Name = ac.Key.Name, Order = ac.Key.Order }
).OrderBy(f => f.Order)
我希望能让你朝着正确的方向前进。