awk:如果> =连续4行以+或 - 开头,则不打印记录

时间:2012-07-16 16:04:26

标签: bash shell awk gawk

我正在尝试使用awk来读取文件,并且只显示不以+或 - 4行或更多次开头的行。 gawk也没关系。每个分组用空行分隔。

以下是文件中的示例,这些是我想要打印的行:

+Host is up.
+Not shown: 95 closed ports, 3 filtered ports
+PORT     STATE SERVICE   VERSION
+23/tcp   open  telnet
+9100/tcp open  jetdirect

-Host is up.
-Not shown: 99 closed ports
-PORT     STATE SERVICE VERSION
-5900/tcp open  vnc

要打印的文件中的样本(不是连续4个或更多):

-Not shown: 76 closed ports, 18 filtered ports
+Not shown: 93 closed ports
PORT    STATE SERVICE VERSION
+514/tcp open  shell

我正在学习如何使用awk,因为我一直在阅读O'Reilly的awk&但是我对这个问题感到有些困惑。此外,如果有人关心,我不介意看到使用shell脚本解决此问题的非awk方法。

谢谢!

2 个答案:

答案 0 :(得分:5)

如果我理解了您的问题,输入文件会将记录作为段落,因此您需要将它们用空行分隔。我认为它适用于下一个脚本:

script.awk的内容:

BEGIN {
        ## Separate records by one or more blank lines.
        RS = ""

        ## Each line will be one field. Both for input and output.
        FS = OFS = "\n"
}

## For every paragraph...
{
        ## Flag to check if I will print the paragraph to output.
        ## If 1, print.
        ## If 0, don't print.
        output = 1

        ## Count how many consecutive rows have '+' or '-' as first
        ## character.
        j = 0

        ## Traverse all rows.
        for ( i = 1; i <= NF; i++ ) {
                if ( substr( $i, 1, 1 ) ~ /+|-/ ) {
                        ++j;
                }
                else {
                        j = 0
                }

                if ( j >= 4 ) {
                        output = 0
                        break
                }
        }

        if ( output == 1 ) {
                print $0 "\n"
        }
}

假设测试输入文件为infile

+Host is up. 
+Not shown: 95 closed ports, 3 filtered ports
+PORT     STATE SERVICE   VERSION

+Host is up. 
+Not shown: 95 closed ports, 3 filtered ports
+PORT     STATE SERVICE   VERSION
+23/tcp   open  telnet
+9100/tcp open  jetdirect

-Host is up. 
-Not shown: 99 closed ports
-PORT     STATE SERVICE VERSION
-5900/tcp open  vnc 

-Not shown: 76 closed ports, 18 filtered ports
+Not shown: 93 closed ports
PORT    STATE SERVICE VERSION
+514/tcp open  shell

运行如下脚本:

awk -f script.awk infile

使用以下输出(第一个记录,因为它没有达到连续四行,而第二个记录因为它们之间有不同的行):

+Host is up.
+Not shown: 95 closed ports, 3 filtered ports
+PORT     STATE SERVICE   VERSION

-Not shown: 76 closed ports, 18 filtered ports
+Not shown: 93 closed ports
PORT    STATE SERVICE VERSION
+514/tcp open  shell

答案 1 :(得分:-1)

awk '{if(NF>3 &&( $0 ~ /\+/ || $0 ~ /-/) ) print $0}' test.txt