Question

我有以下代码正常工作：

success: function (upd_rsp){
  //if email is not register
  if(upd_rsp == "email_no"){
  exstInfo.text("This E-mail is not registered in our Database!");
  exstInfo.addClass("error");
  return false;
  }

  //if email & pass don't match
  if(upd_rsp == "email_pass_no"){
  matchInfo.text("Email and Password don't match!");
  matchInfo.addClass("error");
  return false;
  }

现在，如果我放在那些2＆＃34;如果＆＃34;一个＆＃34;否则＆＃34;声明（下），第二个＆＃34; if＆＃34;没有被执行。我哪里错了？

   else{
   exstInfo.text("");
   exstInfo.removeClass("error");
   return true;
   }

解决方案效果很好。

Answer 1

如果您在执行第二个return之前设置了if值，则在return发送后脚本将停止。

这是您可以采取的众多方法之一：

success: function (upd_rsp){
  //if email is not register
  var email_error = false;
  var pass_error = false;
  if(upd_rsp == "email_no"){
    exstInfo.text("This E-mail is not registered in our Database!");
    exstInfo.addClass("error");
    email_error = true;
  } else {
    exstInfo.text("");
    exstInfo.removeClass("error");
    email_error = false;
  }


  //if email & pass don't match
  if(upd_rsp == "email_pass_no"){
    matchInfo.text("Email and Password don't match!");
    matchInfo.addClass("error");
    pass_error = true;
  } else {
    ....
    pass_error = false;
  }

  if(email_error == true || pass_error == true){
    return false;
  } else {
    return true;
  }

Ajax成功响应

1 个答案: