我有一个实体
public class CommissionSummary {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
@Column(length = 100)
private String advisorCode;
@Column(length = 100)
private String advisorName;
private String advisorCodeParent;
@Column(length = 100)
private String advisorNameParent;
@Column(length = 100)
private String advisorPost;
@Column
private Double percentage;
@Column
private Double diffPercentage;
@Column
private Double saleAmount;
@Column
private Long saleCount;
@Column
**private Double commissionAmount;
@Column
private Integer month;
@Column
private Integer year;**
//Getter Setter
}
屏幕用户正在输入标准以获取2个日期之间的日期。
实施例。从2012年1月1日至2012年7月30日。
在CommissionSummary实体中没有日期列,但它有月份和年份2的单独列。
我想根据月份和年份列从用户提供的日期和日期获取CommissionSummary记录。
那么如何使用Hibernate Criteria / Restrictions实现这一目标呢?
注意:日期字段在用户输入和迄今没有任何意义。
答案 0 :(得分:3)
您可以将标准分解为三个较小标准的分离:
您可以将每个作为两个简单比较的结合来编写。这看起来像(未经过测试!):
int fromYear, fromMonth, toYear, toMonth;
Property year = Property.forName("year");
Property month = Property.forName("month");
session.createCriteria(CommissionSummary.class).add(Restrictions.disjunction()
.add(Restrictions.and(year.eq(fromYear), month.ge(fromMonth))
.add(Restrictions.and(year.gt(fromYear), year.lt(toYear))
.add(Restrictions.and(year.eq(toYear), month.le(toMonth))
);
答案 1 :(得分:0)
没有限制可以做到这一点。您必须创建自己的Criterion子类,以生成相应的SQL,或使用Restrictions.sqlRestriction()
。
在SQL中,在Oracle上,SQL限制可能如下所示:
to_date(c.year || '-' || c.month || '-01', 'YYYY-MM-DD') between :startDate and :endDate)
答案 2 :(得分:-1)
您可以使用HQL选择所需内容:
session.beginTransaction();
session.clear();
Query query = session.createSQLQuery(" from CommissionSummary CS where to_date(CS.year || '-' || CS.month || '-01', 'YYYY-MM-DD') between :startDate and :endDate)"
List result = query.list();
答案 3 :(得分:-1)
感谢您的所有答案@JB Nizet告诉了正确的方法,但这是来自本机SQL。我在下面尝试过成功......
public List<CommissionSummary> getCommissionSummary(AdvisorReportForm advisorReportForm) {
Criteria criteria = getSession().createCriteria(CommissionSummary.class);
if (advisorReportForm.getAdvisorId() != null && advisorReportForm.getAdvisorId() > 0) {
criteria.add(Restrictions.eq("advisorCode", advisorReportForm.getAdvisorId().toString()));
}
if (advisorReportForm.getFromDate() != null && advisorReportForm.getToDate() != null) {
Calendar calFrom = Calendar.getInstance();
calFrom.setTime(advisorReportForm.getFromDate());
Calendar calTo = Calendar.getInstance();
calTo.setTime(advisorReportForm.getToDate());
Criterion crit1 = Restrictions.eq("month", calFrom.get(Calendar.MONTH) + 1);
Criterion crit2 = Restrictions.eq("year", calFrom.get(Calendar.YEAR));
Criterion critMonthYear1 = Restrictions.and(crit1, crit2);
calFrom.add(Calendar.MONTH, 1); // increment loop by month
Criterion critAll = critMonthYear1;
while (calFrom.getTimeInMillis() < calTo.getTimeInMillis()) {
Criterion crit1Loop = Restrictions.eq("month", calFrom.get(Calendar.MONTH) + 1);
Criterion crit2Loop = Restrictions.eq("year", calFrom.get(Calendar.YEAR));
Criterion critMonthYearLoop = Restrictions.and(crit1Loop, crit2Loop);
critAll = Restrictions.or(critAll, critMonthYearLoop);
calFrom.add(Calendar.MONTH, 1); // increment loop by month
}
criteria.add(critAll);
}
return criteria.list();
}
从日期到日期,差异最多可验证6个月。我没有看到很多性能问题。所以用过这个。
这里引用的是生成SQL
SELECT * FROM CommissionSummary this_
WHERE this_.advisorCode=1
AND (((((this_.month=11 AND this_.year=2011) OR (this_.month=12 AND this_.year=2011)) OR (this_.month=1 AND this_.year=2012))
OR (this_.month=2 AND this_.year=2012)) OR (this_.month=3 AND this_.year=2012))