Question

我有一个HTML表单，看起来像这样：

<form name="form1" method="post" action="/confirm.asp">
    <input type="text" name="data1" size="20" value=""><br>
    <input type="text" name="data2" size="20" value=""><br>
    <input type="Submit" name=submit value="Submit">
</form>

我想使用Java将数据传递给data1和data2，并在提交表单时阅读后面的页面。由于这是一个方法=帖子，我不能使用http://somesite.com/confirm.asp?data1=foo&data2=foo。

可以请一位帮忙吗？

Answer 1

/* create a new URL and open a connection */
URL url = new URL("http://somesite.com/confirm.asp");
URLConnection con = url.openConnection();
con.setDoOutput(true);

/* wrapper the output stream of the connection with PrintWiter so that we can write plain text to the stream */
PrintWriter wr = new PrintWriter(con.getOutputStream(), true);

/* set up the parameters into a string and send it via the output stream */
StringBuilder parameters = new StringBuilder();
parameters.append("data1=" + URLEncoder.encode("value1", "UTF-8"));
parameters.append("&");
parameters.append("data2=" + URLEncoder.encode("value2", "UTF-8"));
wr.println(parameters);
wr.close();

/* wrapper the input stream of the connection with BufferedReader to read plain text, and print the response to the console */
BufferedReader br = new BufferedReader(new InputStreamReader(con.getInputStream()));
String line;
while((line = br.readLine()) != null) System.out.println(line);
br.close();

Answer 2

以下是Link的代码。希望这可以帮助你：）

import java.io.FileOutputStream;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.PrintStream;
import java.net.HttpURLConnection;
import java.net.URL;

public class HttpPostForm
{
  public static void main(String[] args)
  {
    try
    {
      URL url = new URL( "http://www.aaaa.com/xyz.asp" );

      HttpURLConnection hConnection = (HttpURLConnection)
                             url.openConnection();
      HttpURLConnection.setFollowRedirects( true );

      hConnection.setDoOutput( true );
      hConnection.setRequestMethod("POST"); 

      PrintStream ps = new PrintStream( hConnection.getOutputStream() );
      ps.print("param1=abcd&amp;param2=10341");
      ps.close();

      hConnection.connect();

      if( HttpURLConnection.HTTP_OK == hConnection.getResponseCode() )
      {
        InputStream is = hConnection.getInputStream();
        OutputStream os = new FileOutputStream("output.html");
        int data;
        while((data=is.read()) != -1)
        {
          os.write(data);
        }
        is.close();
        os.close();
        hConnection.disconnect();
      }
    }
    catch(Exception ex)
    {
      ex.printStackTrace();
    }
  }
}

Answer 3

要用Java编写POST请求，您应该通过URLConnection连接到目标URL，然后在其中写入头边界的字节，边界消息（放置键，值和任何其他请求数据的位置），以及结束边界。

我为我的应用程序编写了一个PostProcess类，它允许异步POST请求上传，键值参数，文件参数（即表单中的文件上传输入）和上传进度跟踪。它还记录服务器响应。

为了尺寸和可读性，我已将代码外部上传到http://textu.be/T

Answer 4

尝试以下代码

String url="www.somesite.com";     
Document doc = Jsoup.connect(url).data("data1", "foo").data("data2","foo")
                .userAgent("Mozilla/5.0 (Windows; U; WindowsNT 5.1; en-US; rv1.8.1.6) Gecko/20070725 Firefox/2.0.0.6")
                .referrer("http://www.google.com").post();

使用Java将数据传递到html POST表单

4 个答案: