Question

b2bHotelSOAPService objsoap = new b2bHotelSOAPService();
        objsoap.Timeout = 20000;
        objsoap.Url = "http://api.hotelspro.com/4.1_test/hotel/b2bHotelSOAP.wsdl";
        string apiKey = Connection.AppSettings("APIKey");
        string destinationId = "LD6J";
        DateTime checkIn = new DateTime(2012, 7, 20);
        DateTime checkOut = new DateTime(2012, 7, 22);
        string strCurrencyCode = "EUR";



        pax[][]rooms=new pax[3][];
        rooms[0] = new pax[3];
        rooms[0][0] = new pax();
        rooms[0][1] = new pax();
        rooms[0][2] = new pax();


        rooms[0][0].paxType = "Adult";
        rooms[0][1].paxType="Adult";
        rooms[0][2].paxType="Child";
        rooms[0][2].age = "6";


        filter[] f = new filter[1];
        f[0] = new filter();
        f[0].filterType = "hotelStar";
        f[0].filterValue = "3";




        getAvailableHotelResponse getres = new getAvailableHotelResponse();

        getres = objsoap.getAvailableHotel(apiKey, destinationId, checkIn, checkOut, strCurrencyCode, "UK", true, rooms, f);

此代码抛出以下错误：

Client found response content type of 'application/wsdl+xml', but expected 'text/xml'.
The request failed with the error message:

Answer 1

如果您在文本编辑器中打开WSDL，您将找到要调用的Web服务的地址

<soap:address location="http://api.hotelspro.com/4.1_test/hotel/b2bHotelSOAP.php"/>

因此，您需要更改正在调用的网址。

objsoap.Url = "http://api.hotelspro.com/4.1_test/hotel/b2bHotelSOAP.php";

你正在调用的.WSDL地址是让.NET找出要生成的类的地址，但实际的调用是上面的.PHP地址的web服务。

客户发现响应内容类型为'application / wsdl + xml'，但预期'text / xml'

1 个答案: