我有2个文件 - 1.csv 和 2.csv 。我可以通过已知的方法用PHP下载 1.csv :
$file = '1.csv';
header('Content-Description: File Transfer');
header('Content-Type: application/jpeg');
header('Content-Disposition: attachment; filename='.basename($file));
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: public');
header('Pragma: public');
header('Content-Length: ' . filesize($file));
ob_clean();
flush();
readfile($file);
但我的目的是下载两个文件的文件内容 - 1.csv 和 2.csv 。有没有人有一些想法如何实现这个? 提前谢谢。
答案 0 :(得分:2)
如果我理解正确,应该这样做。
$file1 = '1.csv';
$file2 = '2.csv';
header('Content-Description: File Transfer');
header('Content-Type: text/comma-separated-values');
header('Content-Disposition: attachment; filename='.basename($file1, '.csv') . '-' . basename($file2, '.csv') . '.csv');
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: public');
header('Pragma: public');
header('Content-Length: ' . (filesize($file1) + filesize($file2)));
ob_clean();
flush();
readfile($file1);
readfile($file2);
考虑对多个文件使用循环,并注意更改CSV文件的Content-Type标头。
答案 1 :(得分:1)
$file1 = '1.csv';
$file2 = '2.csv';
header('Content-Description: File Transfer');
header('Content-Type: application/jpeg');
header('Content-Disposition: attachment; filename="1-2.csv"');
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: public');
header('Pragma: public');
header('Content-Length: ' . (filesize($file1)+filesize($file2)));
ob_clean();
flush();
echo file_get_contents($file1).file_get_contents($file2);
下载2个文件内容的串联