就是这种情况。我有一个我需要提取和设置的URL列表。它的所有变量驱动,但在我提取后,我不知道我的文件夹将被调用。如果我不知道它叫什么,我就不能把CD放进去。
$DL_DIR = /opt/
$URL = http://nginx.org/download/nginx-1.3.3.tar.gz
$FILE=${URL##*/}
$CONFIG = "-- core"
cd "$DL_DIR"
wget $URL
tar xzf $FILE
cd <HOW DO I GO INTO IT?>
./configure "$CONFIG"
make
make install
rm $FILE
如果这不解释,请说。我真的想解决这个问题,但我很难解释它。
因为我想让它适用于任何一组URL,这些URL可能有两种格式,如“.tar.gz”或一种格式“.zip”,并且可能在文件名中有。如“Python2.3.4”或者可能不是“Nginx”,它让它有点棘手。
答案 0 :(得分:1)
#! /bin/bash
#
# Problem:
# find the path of the "root" folder in an archive
#
# Strategy:
# list all folders in the archive.
# sort the list to make sure the shortest path is at the top.
# print the first line
#
# Weak point:
# assumes that tar tf and unzip -l will list files in a certain way
# that is: paths ending with / and that the file-list of unzip -l
# is in the fourth column.
#
LIST_FILES=
FILE=$1
case ${FILE##*.} in
gz)
LIST_FILES="tar tf $FILE"
;;
tgz)
LIST_FILES="tar tf $FILE"
;;
zip)
LIST_FILES='unzip -l '$FILE' | awk "{print \$4}"'
;;
esac
ARCHIVE_ROOT=$(
echo $LIST_FILES | sh |\
grep '/$'|\
sort |\
head -n1
)
# we should have what we need by now, go ahead and extract the files.
if [ -d "$ARCHIVE_ROOT" ]; then
cd "$ARCHIVE_ROOT"
else
# there is no path (whoever made the archive is a jerk)
# ...or the script failed (see weak points)
exit 1
fi
答案 1 :(得分:0)
extract_dir=$(tar -tf $FILE | cut -d/ -f1 | uniq)
cd $extract_dir
或
extract_dir=$(tar -tf $FILE | head -1 | cut -d/ -f1)
cd $extract_dir
或
ls > .dir_list_1 # save current directory listing as hidden file
tar xzf $FILE # extract the $FILE
ls > .dir_list_2 # save the directory listing after extraction...
# ...as another hidden file
# diff two lists saved in hidden files, this will help you get the created dir
# grep '>' symbol, to get the inserted line
# use head to get the dir in case there are multiple lines (not necessary)
# use cut to remove the '>' and get the actual dir name, store in extract_dir
extract_dir=$(diff .dir_list_1 .dir_list_2 | grep '>' | head -1 | cut -d' ' -f2)
# remove temporary files
rm .dir_list_*
cd $extract_dir
答案 2 :(得分:0)
如果您知道$ DL_DIR中只有一个目录,那么您可以使用:
cd `ls -m1`
另一种方法是循环遍历目录的文件:
for filename in "$DL_DIR"/* do echo $filename done;
您可以根据需要执行文件测试和其他检查。
答案 3 :(得分:0)
我说,用$ {FILE ## *。}删除文件的扩展名,然后使用$ {FILE%.ext *}对目录名执行相反的操作:
case ${FILE##*.} in gz) tar xf $FILE cd ${FILE%.tar.gz*} ;; tgz) tar xf $FILE cd ${FILE%.tgz*} ;; zip) unzip $FILE cd ${FILE%.zip*} ;; esac
只是一个小问题:如何知道存档中的目录是否与存档本身具有相同的名称?
答案 4 :(得分:-1)
这个怎么样:
rm -rf tmpdir
mkdir tmpdir && cd tmpdir || exit
wget "$URL" || exit 1
case "$(ls)" in
*.tar.gz|*.tgz)
tar xzf $(ls)
;;
*.zip)
unzip $(ls)
;;
esac
for d in $(ls -d)
do
( cd "$d" 2>/dev/null && ./configure && make && make install; )
done