Question

我不知道发生了什么，我已经一次又一次地在PHP和Javascript中仔细检查了我的代码，但是无法找到任何额外的}，没有相应的{，任何人都可以帮我看看代码？

这是PHP文件，加载函数可以成功加载，但是，当我单击“查看日志”按钮时，会出现上述消息。

function load($DB){
    $dbConnection = mysql_connect($DB['server'], $DB['loginName'], $DB['password']);
    if(!$dbConnection){
        die('Error! ' . mysql_error());
        }
    mysql_select_db($DB['database'], $dbConnection);
    $result = mysql_query("SELECT ClientName FROM Client");

    print "Sort by";
    print "<select id='option'>";
    print "<option value='3'>Tech</option>";
    print "<option value='4'>Client</option>";
    print "</select>";
    print "<input type='button' value='View the log' onclick='viewlog(document.getElementById('option').value)'/>";
    print "<br>";

    print "Tech Name checked in/out from";
    print "<select id='client'>";
    while($row = mysql_fetch_array($result)){
        print "<option value='".$row['ClientName']."'>".$row['ClientName']."</option>";
    }
    print "</select>";
    print "<input type='button' value='Display' onclick='display(document.getElementById('client').value)'/>";
    print "<br>";
    print "<button type='button' onclick='back.php?function=5'>Export the log to .csv</button>";
    print "<br>";
}

function viewlog($DB, $sort){
    print "<h1>repeat</h1>";
    $dbConnection = mysql_connect($DB['server'], $DB['loginName'], $DB['password']);
    if(!$dbConnection){
        die('Error! ' . mysql_error());
        }
    mysql_select_db($DB['database'], $dbConnection);
    $query = "SELECT * 
                FROM Tech AS T, Client AS C, Site AS S, Log AS L 
                WHERE T.TechID=L.TechID AND C.ClientID=L.ClientID AND S.SiteID=L.SiteID ";
    if($sort=="Tech")
        $query .= "ORDER BY T.TechName ASC, L.Time DESC";
    else if($sort=="Client")
        $query .= "ORDER BY C.ClientName ASC, L.Time DESC";
    $result = mysql_query($query) or die('Error! ' . mysql_error());; 
    print "Real-Time check in/check out<br>";
    print "<table><th><td>Tech</td><td>Client</td><td>Site</td>";
    print "<td>Date and Time</td><td>Type</td></th>";
    while($row = mysql_fetch_array($result)){
        print "<tr><td>".$row['TechName']."</td>";
        print "<td>".$row['ClientName']."</td>";
        print "<td>".$row['SiteName']."</td>";
        print "<td>".$row['Time']."</td>";
        print "<td>".$row['Type']."</td></tr>";
        }
    print "</table>";
}

function export($DB){
    $dbConnection = mysql_connect($DB['server'], $DB['loginName'], $DB['password']);
    if(!$dbConnection){
        die('Error! ' . mysql_error());
        }
    mysql_select_db($DB['database'], $dbConnection);
    $result = mysql_query("SELECT TechName, ClientName, SiteName, Time, Type
                            INTO OUTFILE 'result.csv'
                            FIELDS TERMINATED BY ',' OPTIONALLY ENCLOSED by '\"'
                            LINES TERMINATED BY '\n'
                            FROM Tech AS T, Client AS C, Site AS S, Log AS L
                            WHERE T.TechID=L.TechID AND C.ClientID=L.ClientID AND S.SiteID=L.SiteID
                            ORDER BY L.Time DESC");
    $Time = date('Y_m_d_H_i');
    $fileName = "Report_" + $Time;
    header('Content-type: text/csv'); 
    header('Content-Disposition: attachment; filename="'.$fileName.'.csv"'); 
    readfile('result.csv');
}

$function = $_GET['function'];
if($function==0)
    load($DB);
elseif($function==3)
    viewlog($DB, "Tech");
elseif($function==4)
    viewlog($DB, "Client");
elseif($function==5)
    export($DB);

以下是Javascript代码：

function load(){
var xmlhttp;
if (window.XMLHttpRequest){ // code for IE7+, Firefox, Chrome, Opera, Safari
    xmlhttp = new XMLHttpRequest();
}else{ // code for IE6, IE5
    xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}               

xmlhttp.onreadystatechange = function(){
    //document.getElementById("action").innerHTML=xmlhttp.status;
    if (xmlhttp.readyState == 4 && xmlhttp.status == 200){
        document.getElementById("action").innerHTML=xmlhttp.responseText;       
    }
}
var num = 0;
xmlhttp.open("GET","back.php?function="+num, true);
xmlhttp.send();
}

function viewlog(num){
var xmlhttp;
if (window.XMLHttpRequest){ // code for IE7+, Firefox, Chrome, Opera, Safari
    xmlhttp = new XMLHttpRequest();
}else{ // code for IE6, IE5
    xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}               

xmlhttp.onreadystatechange = function(){
    if (xmlhttp.readyState == 4 && xmlhttp.status == 200){
        document.getElementById("View").innerHTML=xmlhttp.responseText;         
    }
}
xmlhttp.open("GET","back.php?function="+num, true);
xmlhttp.send();
}

我试图在js文件中隐藏viewlog函数，也是为了PHP文件的viewlog函数中的内容，但是这两个动作仍然发出相同的消息，我真的不知道如何调试它。有人可以帮我一把吗？

Answer 1

我认为浏览器在使用与javascript字符串相同的引用时会遇到问题（你在两者中都这样做，但是我只是举了一个例子）：

onclick='viewlog(document.getElementById('option').value)'

到

onclick='viewlog(document.getElementById(&quot;option&quot;).value)'

未捕获的SyntaxError：意外的令牌}

1 个答案: