Question

我正在使用SAX Parser来处理我正在处理的Android应用程序，并且我很难尝试保存Project的名称标签而不被覆盖。这里的问题是项目中的名称标签被许可证中的名称标签覆盖，因为标签是相同的。剩下的就是解析得很漂亮。此外，通过将GET请求传递给API来生成此xml，因此我无法对其进行编辑。有没有办法可以省略许可证字段中的名称标签，或者尝试了解我在文档内部的位置，这是一个问题，因为SAX甚至被驱动。此外，我意识到我可以使用DOM轻松完成这项工作，但现在我已经走得太远而无法切换到DOM。我已经附加了我的XML处理代码和我试图解析的xml文件的片段。

由于

@Override
public void startElement (String namespaceURI, String localName, String qName, Attributes attributes) throws SAXException 
{
    buffer.setLength(0);

    if (localName.equalsIgnoreCase("result"))
    {
        results = new ArrayList <Result> ();
    }

    if (localName.equalsIgnoreCase("project"))
    {
        result = new Result ();
    }

    if (localName.equalsIgnoreCase("name"))
    {
        result.name = buffer.toString ();
        Log.v("PROJECT NAME: ", result.name);
    }
} // end of startElement ()

@Override
public void endDocument () throws SAXException
{}

@Override
public void endElement (String namespaceURI, String localName, String qName) throws SAXException
{       
    if (localName.equalsIgnoreCase("project") || localName.equalsIgnoreCase("account"))
    {
            this.entries++;
            results.add(result);
    }

    else if (localName.equalsIgnoreCase("id"))
    {
        result.id = buffer.toString ();
        Log.v("Id: ", result.id);
    }

    else if (localName.equalsIgnoreCase("created_at"))
    {
        try 
        {
            result.date_created = ResultHandlerProject.DATE_FORMAT.parse(buffer.toString());
        } 
        catch (ParseException e) 
        {
            e.printStackTrace();
        }
    }

    else if (localName.equalsIgnoreCase("updated_at"))
    {
        try 
        {
            result.date_updated = ResultHandlerProject.DATE_FORMAT.parse(buffer.toString());
        } 
        catch (ParseException e) 
        {
            e.printStackTrace();
        }
    }

    else if (localName.equalsIgnoreCase("description"))
    {
        result.description = buffer.toString ();
    }

    else if (localName.equalsIgnoreCase("homepage_url"))
    {
        result.url_homepage = buffer.toString ();
    }

    else if (localName.equalsIgnoreCase("download_url"))
    {
        result.url_download = buffer.toString ();
    }

    else if (localName.equalsIgnoreCase("medium_logo_url"))
    {
        result.image_link = buffer.toString ();
    }

    else if (localName.equalsIgnoreCase("user_count"))
    {
        result.user_count = buffer.toString ();
    }

    else if (localName.equalsIgnoreCase("average_rating"))
    {
        result.rating = buffer.toString ();
    }

    else if (localName.equalsIgnoreCase("rating_count"))
    {
        result.rating_count = buffer.toString ();
    }

    else if (localName.equalsIgnoreCase("analysis_id"))
    {
        result.analysis_id = buffer.toString ();
    }

    else if (localName.equalsIgnoreCase("nice_name"))
    {
        result.license_full_name = buffer.toString ();
        Log.v("License Full Name: ", result.license_full_name);
    }

} // end of endElement ()

示例XML文件：

<result>
<project>
<id>6050</id>
<name>FirePHP</name>
<created_at>2007-06-16T04:03:13Z</created_at>
<updated_at>2012-07-01T15:05:23Z</updated_at>
<description>
FirePHP 
<homepage_url>http://www.firephp.org/</homepage_url>
<download_url>http://www.firephp.org/</download_url>
<url_name>FirePHP</url_name>
<medium_logo_url>
https://s3.amazonaws.com/cloud.ohloh.net/attachments/6638/FirePHP_Large_White_med.png
</medium_logo_url>
<small_logo_url>
https://s3.amazonaws.com/cloud.ohloh.net/attachments/6638/FirePHP_Large_White_small.png
</small_logo_url>
<user_count>145</user_count>
<average_rating>4.11765</average_rating>
<rating_count>34</rating_count>
<analysis_id>8910317</analysis_id>
<licenses>
<license>
<name>bsd</name>
<nice_name>BSD Copyright</nice_name>
</license>
</licenses>
</project>

Answer 1

您可以通过简单的方式解决问题。

在您的类处理程序中创建一些标志。

private boolean inProject = false;
private boolean inLicense = false;

控制这些标志，就像我在下面给你看的那样。

   @Override
   public void startElement (String namespaceURI, String localName, String qName, Attributes attributes) throws SAXException 
   {
      if (localName.equalsIgnoreCase("project")) {
           this.inProject = true;
      }
      else if (localName.equalsIgnoreCase("license")) {
           this.inLicense = true;
      }
   }

   @Override
   public void endElement (String namespaceURI, String localName, String qName) throws SAXException
   {       
       if (localName.equalsIgnoreCase("name") {
           if(inProject) { 
              //Set your project name here.
              this.inProject = false;
           }
           else if (inLicense) {
              //Set your lencense name here.
              this.inLicense = false;
           }
       }
    }

让我知道它是否有效。

SAX Parser相同的标签覆盖值

1 个答案: