我正在尝试在python中构建一个字典。代码如下所示:
dicti = {}
keys = [1, 2, 3, 4, 5, 6, 7, 8, 9]
dicti = dicti.fromkeys(keys)
values = [2, 3, 4, 5, 6, 7, 8, 9]
如何使用列表填充字典值?是否有内置功能?
结果应该是这样的:
dicti = {1:2,2:3,3:4,4:5,5:6,6:7,7:8,8:9}
答案 0 :(得分:21)
如果您有两个列表keys
且对应 values
:
keys = [1, 2, 3, 4, 5, 6, 7, 8, 9]
values = [2, 3, 4, 5, 6, 7, 8, 9]
dicti = dict(zip(keys, values))
dicti
现在是{1: 2, 2: 3, 3: 4, 4: 5, 5: 6, 6: 7, 7: 8, 8: 9}
答案 1 :(得分:0)
这样可行,但列表必须大小相同(删除键列表中的9)
keys = [1, 2, 3, 4, 5, 6, 7, 8]
values = [2, 3, 4, 5, 6, 7, 8, 9]
dicti = {}
for x in range(len(keys)):
dicti[keys[x]] = values[x]
答案 2 :(得分:0)
针对您的具体情况的另一名班轮人员是
dicti = {k:v for k, v in enumerate(values, start=1)}
结果是:
print(dicti)
{1:2,2:3,3:4,4:5,5:6,6:7,7:8,8:9}