Question

我写了一个脚本来返回数据库中的案例记录。当实际有两条记录时，我正在为我的mysql查询返回一条记录。这是我要回来的：

{ "cases": [ {"name":"Test Case for App","number":"3846"}] }

我应该看到：

{ "cases": [ {"name":"Test Case for App","number": "2903"}, {"name":"Test Case 2","number": "2856"} ] }

这是我的来源：

$sql = "select * from cases as c join contacts_cases as conc on c.id = conc.case_id where conc.contact_id = '1b360507'";
$query = mysql_query($sql);  

// If we find a match, create an array of data, json_encode it and echo it out  
if (mysql_num_rows($query) > 0)  
{  
    $row = mysql_fetch_assoc($query);  
    $response = array(  
        'name' => $row['name'],  
        'number' => $row['case_number']
    );  

    echo '{ "cases": [ ',  json_encode($response), "] }";

Answer 1

如果您期望多个结果，请尝试

if (mysql_num_rows($query) > 0)  
{  
    $responses = array();
    while($row = mysql_fetch_assoc($query)) {
        $responses[] = array(  
            'name' => $row['name'],  
            'number' => $row['case_number']
        );  
    }
    echo '{"cases": ' . json_encode($responses) . '}';
}

Answer 2

你需要循环遍历所有行，你只需要一行。

另外，不要尝试自己构建JSON。按照你想要的方式制作数组json_encode。

$cases = array();
while ($row = mysql_fetch_assoc($query)) {
    $cases[] = array(  
        'name'   => $row['name'],  
        'number' => $row['case_number']
    );
}

echo json_encode(array('cases' => $cases));

在PHP数组中显示多行

2 个答案: