Question

可能重复：
how can I iterate through two lists in parallel in Python?

我有3个这样的列表：

name = ['sam', 'john', 'napoleon', 'tanaka', 'ming']
country = ['USA', 'England', 'France', 'Japan', 'China']
age = [23, 41, 19, 16, 55]

我希望输出如下：

sam; USA; 23
john; England; 41
napoleon; France; 19
tanaka; Japan; 16
ming; China; 55

任何帮助都会很棒。提前谢谢

Answer 1

您可以使用zip()：

name = ['sam', 'john', 'napoleon', 'tanaka', 'ming']
country = ['USA', 'England', 'France', 'Japan', 'China']
age = [23, 41, 19, 16, 55]
for x,y,z in zip(name,country,age):
    print("{0}; {1}; {2}".format(x,y,z))

或使用map()：

mapp=map(lambda x,y,z:"; ".join((x,y,str(z))),name,country,age)
for x in mapp:
    print(x)

<强>输出：

sam; USA; 23
john; England; 41
napoleon; France; 19
tanaka; Japan; 16
ming; China; 55

Answer 2

name = "sam john napoleon tanaka ming".split()
country = "USA England France Japan China".split()
age = [23, 41, 19, 16, 55]

print "\n".join(["%s; %s %d" % (x) for x in zip(name,country,age)])

Answer 3

假设列表长度相同：

for i in range(len(name)):
    print '%s; %s; %s' %(name[i], country[i], age[i])

更新：这假设你使用的是Python 3.x.对于2.x，使用xrange进行一般性能改进。可替换地：

for i in range(len(name)):
    print '{0}; {1}; {2}'.format{name[i], country[i], age[i]}

Answer 4

如果你知道它们都具有相同的长度，那么你可以这样做：

name = ['sam', 'john', 'napoleon', 'tanaka', 'ming']
country = ['USA', 'England', 'France', 'Japan', 'China']
age = [23, 41, 19, 16, 55]

i = 0

for n in name:
    print name[i] + '; ' + country[i] + '; ' + str(age[i])
    i++

Answer 5

我的2美分; - ）

使用itertools模块中的生成器：

from itertools import izip

nlist = ['%s; %s; %s' %t for t in izip(name, country, age)]

我可以在python中集成多个列表吗？

5 个答案: