XCode 4.2 - Openssl构建错误

Question

我已成功为iPhone模拟器创建了OpenSSL库。我已成功导入所有标头和库。但是，我在构建项目时遇到问题，XCode告诉我结构X509_ALGOR 的不完整定义。这是代码：

- (NSData *)encodePBEWithMD5AndDESData:(NSData *)inData password:(NSString *)password direction:(int)direction
{   
// Change salt and number of iterations for your project !!!

static const char gSalt[] =
{
    (unsigned char)0xaa, (unsigned char)0xd1, (unsigned char)0x3c, (unsigned char)0x31,
    (unsigned char)0x53, (unsigned char)0xa2, (unsigned char)0xee, (unsigned char)0x05
};

unsigned char *salt = (unsigned char *)gSalt;
int saltLen = strlen(gSalt);
int iterations = 15;

EVP_CIPHER_CTX cipherCtx;


unsigned char *mResults;         // allocated storage of results
int mResultsLen = 0;

const char *cPassword = [password UTF8String];

unsigned char *mData = (unsigned char *)[inData bytes];
int mDataLen = [inData length];    

SSLeay_add_all_algorithms();
X509_ALGOR *algorithm = PKCS5_pbe_set(NID_pbeWithMD5AndDES_CBC,
                                      iterations, salt, saltLen);


memset(&cipherCtx, 0, sizeof(cipherCtx));

if (algorithm != NULL)
{
    EVP_CIPHER_CTX_init(&(cipherCtx));

    **if (EVP_PBE_CipherInit(algorithm->algorithm, cPassword, strlen(cPassword),
                           algorithm->parameter, &(cipherCtx), direction))**
    {

        EVP_CIPHER_CTX_set_padding(&cipherCtx, 1);

        int blockSize = EVP_CIPHER_CTX_block_size(&cipherCtx);
        int allocLen = mDataLen + blockSize + 1; // plus 1 for null terminator on decrypt
        mResults = (unsigned char *)OPENSSL_malloc(allocLen);


        unsigned char *in_bytes = mData;
        int inLen = mDataLen;
        unsigned char *out_bytes = mResults;
        int outLen = 0;

发现未完全定义了结构X509_ALGOR的指针，即“算法”。我对此没有任何线索。有人可以帮帮我吗？

if (EVP_PBE_CipherInit(algorithm->algorithm, cPassword, strlen(cPassword),
                           algorithm->parameter, &(cipherCtx), direction))

Answer 1

我不确定是否适合回答我自己的问题。但是，如果有人遇到同样的问题我会这样做，他/她可能会得到一些帮助。

上面提到的代码的问题是链接器标志。在“Build Settings”下的“Other Linker Flags”中设置“-ObjC -load_all”后，问题就消失了。

问候。