Question

我一直在编写MySQL查询很长一段时间，但在完成此问题时我完全觉得自己像个新手，我似乎无法弄清楚如何简化这个查询。基本上我只是想从我们的数据库中生成以逗号分隔的收入列表，最终会插入谷歌图表。我也必须为“过去的31天”制作一个，所以除非我弄清楚如何简化这一点，否则我有点紧张。

我表中的我的数据库列是......

time：订单以int（）（UNIX时间戳格式）
的形式出现
价格：十进制（10,2）
的订单金额

SELECT
 CONCAT(
 (SELECT SUM(price) FROM orders WHERE time < (UNIX_TIMESTAMP() - (6 * 86400)) AND time > (UNIX_TIMESTAMP() - (7 * 86400))),
 ',',
 (SELECT SUM(price) FROM orders WHERE time < (UNIX_TIMESTAMP() - (5 * 86400)) AND time > (UNIX_TIMESTAMP() - (6 * 86400))),
 ',',
 (SELECT SUM(price) FROM orders WHERE time < (UNIX_TIMESTAMP() - (4 * 86400)) AND time > (UNIX_TIMESTAMP() - (5 * 86400))),
 ',',
 (SELECT SUM(price) FROM orders WHERE time < (UNIX_TIMESTAMP() - (3 * 86400)) AND time > (UNIX_TIMESTAMP() - (4 * 86400))),
 ',',
 (SELECT SUM(price) FROM orders WHERE time < (UNIX_TIMESTAMP() - (2 * 86400)) AND time > (UNIX_TIMESTAMP() - (3 * 86400))),
 ',',
 (SELECT SUM(price) FROM orders WHERE time < (UNIX_TIMESTAMP() - 86400) AND time > (UNIX_TIMESTAMP() - (2* 86400)) ),
 ',',
 (SELECT SUM(price) FROM orders WHERE time > (UNIX_TIMESTAMP() - 86400))
 ) as chart_rev 
FROM orders_basic
LIMIT 0,1

如果可能的话，我需要以24小时为单位增加它。

一如既往，非常感谢任何帮助。谢谢！

解

请注意：仔细查看结果，它们可能在那里，只是顺序错误，如果是，请改变您的排序。

SELECT GROUP_CONCAT(total_sum) AS sum_list FROM
(
    SELECT
        FLOOR((UNIX_TIMESTAMP() - time) / 86400) AS date,
        SUM(price) AS total_sum
    FROM
        orders_basic
    WHERE
        is_testorder < 1
          AND FROM_UNIXTIME(time) > DATE_SUB(NOW(), INTERVAL 1 WEEK)
    GROUP BY
        date
) AS s

Answer 1

这样的事可能吗？

SELECT GROUP_CONCAT(total_sum) AS sum_list FROM
(
    SELECT
        DATE(FROM_UNIXTIME(time)) AS date,
        SUM(price) AS total_sum
    FROM
        orders
    WHERE
        FROM_UNIXTIME(time) > DATE_SUB(NOW(), INTERVAL 1 MONTH)
    GROUP BY
        date
) AS s

这应该为您提供逗号分隔的上个月销售金额列表。但它会按日期分组，而不是24小时增量（截止日期为午夜，根据time列。）

MySQL简化了这个查询？

1 个答案: